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3 years ago

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PLEASE HELP ME QUICKLY WILL GIVE BRAINLIEST TO WHOEVER ANSWERS FIRST....

1 answer:

sp2606 [1]3 years ago

8 0

Answer:

h20

Explanation:

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what is the focalength of the combination of two thin renses of power -5D and -2D placeci in contact with each other?

Ghella [55]

Answer:

f = - 0.143 m = - 14.3 cm

Explanation:

First, we will calculate the power of the combination of lenses:

P = P₁ + P₂

where,

P = Power of Combination = ?

P₁ = Power of first lens = - 5D

P₂ = Power of second lens = - 2D

Therefore,

P = - 5D - 2D

P = - 7D

Now, the focal length can be given as:

$f = \frac{1}{P} \\\\f = \frac{1}{-\ 7\ D} \\\\$

<u>f = - 0.143 m = - 14.3 cm</u>

Negative focal length indicates that combination will act as diverging lens.

6 0

3 years ago

Derive the dimension of Power

stellarik [79]

Answer:

The dimension of power is energy divided by the time or $[ML^2T^-3]$

Explanation:

Power = $\frac {Work Done}{Time}$

We can derive Dimensions of Power from both formula.

Power = Force * Velocity

As,

Force = mass * acceleration

Therefore, Dimensions of

Force = $[M]*[LT^-2] = [MLT^-2]$

Since,

Velocity = $\frac{Length}{Time}$

Now, Dimension of

Velocity = $[LT^-1]$

We have Both Dimensions,Now we can derive Dimensions Of Power,

Power = Force * Velocity

Power = $[MLT^-2] * [LT^-1]$

Power = $[ML^2T^-3]$

7 0

3 years ago

Displacement vectors of 3 m and 5 m in the same direction combine to make a displacement vector that is _____ in magnitude.

Alona [7]

The correct answer is 8 meters.

4 0

4 years ago

Read 2 more answers

A beam of alpha particles ( q = +2e, mass = 6.64 x 10-27 kg) is accelerated from rest through a potential difference of 1.8 kV.

Mrrafil [7]

Answer:

The magnetic field required required for the beam not to be deflected is $B = 0.0036T$

Explanation:

From the question we are told that

The charge on the particle is $q = +2e$

The mass of the particle is $m = 6.64 *10^{-27} kg$

The potential difference is $V_a = 1.8 kV = 1.8 *10^{3} V$

The potential difference between the two parallel plate is $V_b = 120 V$

The separation between the plate is $d = 8 mm = \frac{8}{1000} = 8*10^{-3}m$

The Kinetic energy experienced by the beam before entering the region of the parallel plate is equivalent to the potential energy of the beam after the region having a potential difference of 1.8kV

$KE_b = PE_b$

Generelly

$KE_b = \frac{1}{2} m v^2$

And $PE_b = q V_a$

Equating this two formulas

$\frac{1}{2} mv^2 = q V_a$

making v the subject

$v = \sqrt{\frac{q V_a}{2 m} }$

Substituting value

$v = \sqrt{\frac{ 2* 1.602 *10^{-19} * 1.8 *10^{3}}{2 * 6.64 *10^{-27}} }$

$v = 41.65*10^4 m/s$

Generally the electric field between the plates is mathematically represented as

$E = \frac{V_b}{d}$

Substituting value

$E = \frac{120}{8*10^{-3}}$

$E = 15 *10^3 NC^{-1}$

the magnetic field is mathematically evaluate

$B = \frac{E}{v}$

$B = \frac{15 *10^{3}}{41.65 *10^4}$

$B = 0.0036T$

6 0

3 years ago

If you adjust the brightness of a light until it matches the intensity of sourness of the taste of a lemon, you are engaging in

Butoxors [25]

Unrestricted Submarine Warfare

6 0

4 years ago