3 years ago

6 times a number is greater than 20 more than that number what are the possible values of that number

1 answer:

4 0

Solve 6x>x+20.
6x-x>20
5x>20
x>4

Answer: all values of x (including decimals and irrationals) greater than 4 will satisfy the given requirement that 6 time x is greater than x+20.

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Step-by-step explanation:

|x - 3| < x – 3

1. Separate the inequality into two separate ones.

(1) x – 3 < x – 3

(2) x – 3 < -(x – 3)

2. Solve each equation separately

(a) Equation (1)

$\begin{array}{rcl}x - 3 & < & x - 3\\x & < & x\\\end{array}\\\text{This is impossible. No solutions exist.}$

(b) Equation (2)

$\begin{array}{rcl}x - 3 & < & -(x - 3)\\x - 3 & < & -x + 3\\x &$

For example, if x = 0, we get

|0 - 3| < 0 - 3 or

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