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vekshin1
3 years ago
15

Suppose two distinct parallelograms lie in a plane. What is the LARGEST number of points at which they can intersect?

Mathematics
2 answers:
Natalija [7]3 years ago
8 0
I had to look for the figure and here is the answer:

Since the given figure are two distinct parallelograms that intersect with each other and lie in a plane, the LARGEST number of points at which they can intersect would be 8 points. You just had to count the intersections based on the illustration.
12345 [234]3 years ago
7 0

Answer:

8

Step-by-step explanation:

USA TEST PREP ANSWER

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In circle F with m \angle EFG= 122m∠EFG=122 and EF=16EF=16 units, find the length of arc EG. Round to the nearest hundredth.
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Given:

In circle F, m\angle EFG=122^\circ,\ EF=16 units.

To find:

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Solution:

It is given that, m\angle EFG=122^\circ,\ EF=16 units. It means the central angle of arc EG is 122 degrees and the radius of the circle F is 16 units.

Formula for arc length is:

s=2\pi r\times \dfrac{\theta}{360^\circ }

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Putting r=16,\ \theta=122^\circ,\ \pi=3.14, we get

s=2(3.14)(16)\times \dfrac{122^\circ}{360^\circ }

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s\approx 34.05

Therefore, the length of arc EG is 34.05 units.

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