A car travels 65 km in 45 minutes what is the average speed of the car in km/h

2 answers:

5 0

So to begin your problem, you know that your car already has an average which is 65km/45 mins. The problem wants you to change this to km/hr. This means that you need to convert minutes to hours. A simple way to do this is by using fractions.
Set your problem up with fractions similar to this:
65km/45 mins x 60 mins/1 hr.
the whole point is to cancel out your minutes, and leave the hours as your new unit for the denominator
65km/45 x 60/1 hr.
now you want to reduce (I divided the first fraction by 5)
13km/9 x 60/1 hr.
780km/9hrs.
That would be your answer. If someone can double check my math that would be fantastic.

mestny [16]2 years ago

3 0

65km in 45 min
1 hour=1h=60min
45/60=3/4
65km=3/4hour
multiply both sides by 4/3 to clear fraction
260/3=1 hour
86 2/3 =1 hour
aprox
86.666666666 km per hour

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Let f (x) = 3x − 1 and ε > 0. Find a δ > 0 such that 0 < ∣x − 5∣ < δ implies ∣f (x) − 14∣ < ε. (Find the largest

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Answer:

This proves that f is continous at x=5.

Step-by-step explanation:

Taking f(x) = 3x-1 and $\varepsilon>0$ , we want to find a $\delta$ such that $|f(x)-14|$

At first, we will assume that this delta exists and we will try to figure out its value.

Suppose that $|x-5|$ . Then

$|f(x)-14| = |3x-1-14| = |3x-15|=|3(x-5)| = 3|x-5|< 3\delta$ .

Then, if $|x-5|$ , then $|f(x)-14|$ . So, in this case, if $3\delta \leq \varepsilon$ we get that $|f(x)-14|$ . The maximum value of delta is $\frac{\varepsilon}{3}$ .