Answer:

Step-by-step explanation:
The given initial value problem is;

Let

Differentiating both sides of equation (1) with respect to
, we obtain:

Differentiating both sides of equation (2) with respect to
gives:

From equation (1),

Putting t=0 into equation (2) yields

Also putting t=0 into equation (3)

The system of first order equations is:

Answer:
Firstly
f(x)=3x-2=y then
Interchanging x and y we get
x=3y-2
x+2=3y
y=(x+2)/3
f-1(x)=(x+2)/3
f-1(13)=(13+2)/3
f-1(13)=5
Answer:
Option A,
± 
Step-by-step explanation:
<u>Step 1: Add 29 to both sides</u>



<u>Step 2: Square root both sides</u>

± 
Answer: Option A,
± 