Answer:
a)Q=131.1 MJ
b)Q=54 MJ
Explanation:
Given that
Mass ,m=200 kg
Specific heat Cp=0.46 J/g°C
Cp=0.46 KJ/kg°C
Heat of fusion = 270 J/g
Heat of fusion = 270 KJ/kg
Melting point temperature = 1450°C
a)
Initial temperature = 25°C
Final temperature=1450°C
Heat required to rise temperature from 25°C to 1450°C.
Q= m CpΔT
Q=200 x 0.46 x (1450-25) KJ
Q=131,100 KJ
Q=131.1 MJ
b)
Heat required to transform from solid phase to liquid phase
Q= Mass x heat of fusion
Q=200 x 27 KJ
Q=54,000 KJ
Q=54 MJ
Answer:
do you have a pic or link to see ?
Answer:
where IS THE PICURE OF THE RED DESK? sorry for caps
Explanation:
This question is not complete, the complete question is;
The stagnation chamber of a wind tunnel is connected to a high-pressure air bottle farm which is outside the laboratory building. The two are connected by a long pipe of 4-in inside diameter. If the static pressure ratio between the bottle farm and the stagnation chamber is 10, and the bottle-farm static pressure is 100 atm, how long can the pipe be without choking? Assume adiabatic, subsonic, one-dimensional flow with a friction coefficient of 0.005
Answer:
the length of the pipe is 11583 in or 965.25 ft
Explanation:
Given the data in the question;
Static pressure ratio; p1/p2 = 10
friction coefficient f = 0.005
diameter of pipe, D =4 inch
first we obtain the value from FANN0 FLOW TABLE for pressure ratio of ( p1/p2 = 10 )so
4fL / D = 57.915
we substitute
(4×0.005×L) / 4 = 57.915
0.005L = 57.915
L = 57.915 / 0.005
L = 11583 in
Therefore, the length of the pipe is 11583 in or 965.25 ft
The correct statement is: a higher than a normal voltage drop could indicate high resistance. Technician B is correct.
<h3>Ohm's law</h3>
Ohm's law states that the current flowing through a metallic conductor is directly proportional to the voltage provided all physical conditions are constant. Mathematically, it is expressed as
V = IR
Where
V is the potential difference
I is the current
R is the resistance
<h3>Technician A</h3>
High resistance causes an increase in current flow
V = IR
Divide both side by I
R = V / I
Thus, technician A is wrong as high resistance suggest low current flow
<h3>Technician B</h3>
Higher than normal voltage drop could indicate high resistance
V = IR
Thus, technician B is correct as high voltage indicates high resistance
<h3>Conclusion </h3>
From the above illustration, we can see that technician B is correct
Learn more about Ohm's law:
brainly.com/question/796939