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MAVERICK [17]
3 years ago
11

A rubber wheel on a steel rim spins freely on a horizontal axle that is suspended by a fixed pivot at point P. When the wheel sp

ins at a rate of 4.00 rev/s, it precesses smoothly about point P in a horizontal plane with a period of 3.50 s. The wheel's outer radius is 15.0 cm, and its total mass is measured to be 1.12 kg, 60% of this being the spinning wheel, and 40% its axle assembly. The wheel and its axle are both symmetric about the middle of the wheel, and the pivot point P is 4.70 cm from the wheel's middle.
a. its axle considered as a body.
b. What is the direction of the net torque on the wheel about the pivot point P?
c. If the wheel is spinning counterclockwise (0) as seen from point B on the wheel's axle, what is the direction of its spin angular momentum referenced to the diagram?
d. As seen from point A above the pivot, which way is the wheel precessing (C or O)? Please give your reasoning.
e. Using this information, determine the moment of inertia I of the wheel about its axle. Please be sure your work is clear.
Engineering
1 answer:
Nimfa-mama [501]3 years ago
3 0

Answer:

stan lee

Explanation:

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Tech A says that 18 AWG wire is larger than 12 AWG wire. Tech B says that the larger the diameter of the conductor, the more ele
shutvik [7]

Answer:

Both of them are wrong

Explanation:

The two technicians have given the wrong information about the wires.

This is because firstly, a higher rating of AWG means it is smaller in diameter. Thus, the diameter of a 18 AWG wire is smaller than that of a 12 AWG wire and that makes the assertion of the technician wrong.

Also, the higher the resistance, the smaller the cross sectional area meaning the smaller the diameter. A wire with bigger cross sectional area will have a smaller resistance

So this practically makes the second technician wrong too

8 0
3 years ago
(a) Calculate the heat flux through a sheet of steel that is 10 mm thick when the temperatures oneither side of the sheet are he
aleksandr82 [10.1K]

Answer:

do the wam wam

Explanation:

6 0
3 years ago
The viscosity of a fluid is 10 be measured by a viscometer constructed of two 75-cm-long concentric cylinders. The outer diamete
a_sh-v [17]

Answer:

0.023 Pa*s

Explanation:

The surface area of the side of the inner cylinder is:

A = π*d*l

A = π*0.15*0.75 = 0.35 m^2

At 200 rpm the inner cylinder has a tangential speed of:

u = w * r

u = w * d/2

w = 200 rpm * 2π / 60 = 20.9 rad/s

u = 20.9 * 0.15 / 2 = 1.57 m/s

The torque is of 0.8 N*m, this means that the force is:

T = F * r

F = T / r

F = 2*T / d

For Newtoninan fluids with two plates moving respect of each other with a  fluid between the viscous friction force would be:

F = μ*A*u / y

Where

μ: viscocity

y: separation between pates

A: surface area of the plates

Then:

2*T / d = μ*A*u/y

Rearranging:

μ = 2*T*y / (d*A*u)

μ = 2*0.8*0.0012 / (0.15*0.35*1.57) = 0.023 Pa*s

5 0
3 years ago
A gas pressure difference is applied to the legs of a U-tube manometer filled with a liquid with specific gravity of 1.7. The ma
MArishka [77]

Answer:

5320.6 Pascal

Explanation:

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Pressure difference in Manometer is a function of density,gravity and the height difference of the liquid.

Pressure difference = density x acceleration due to gravity x difference in height of liquid

Density of liquid = specific gravity of object x density of water.

Density of water = 997 kg/m^3

Specific gravity of liquid = 1.7

Density of liquid = 997 x 1.7 =1694.9kg/m^3

g= 9.81 m/s^2

h =320mm = 0.320m

Pressure difference = 1694.9 x 9.81 x 0.320 = 5320.6 Pascal

3 0
3 years ago
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nordsb [41]

Answer:

False

Explanation:

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