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Bingel [31]
3 years ago
11

Giving out 100 coins cuz why not?​

Engineering
1 answer:
inysia [295]3 years ago
7 0

Answer:

HI

Explanation:

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Briefly discuss if it would be better to operate with pumps in parallel or series and how your answer would change as the steepn
Aleksandr [31]

Answer:

1) In series, the combined head will move from point 1 to point 2 in theory. However, practically speaking, the combined head and flow rate will move along the system curve to point 3.

2) In parallel, the combined head and volume flow will move along the system curve from point 1 to point 3.

Explanation:

1) Pump in series:

When two or more pumps are connected in series, their resulting pump performance curve will be obtained by adding their respective heads at the same flow rate as shown in the first diagram attached.

In the first diagram, we have 3 curves namely:

- system curve

- single pump curve

- 2 pump in series curve

Also, we have points labeled 1, 2 and 3.

- Point 1 represents the point that the system operates with one pump running.

- Point 2 represents the point where the head of two identical pumps connected in series is twice the head of a single pump flowing at the same rate.

- Point 3 is the point where the system is operating when both pumps are running.

Now, since the flowrate is constant, the combined head will move from point 1 to point 2 in theory. However, practically speaking, the combined head and flow rate will move along the system curve to point 3.

2) Pump in parallel:

When two or more pumps are connected in parallel, their resulting pump performance curve will be obtained by adding their respective flow rates at same head as shown in the second diagram attached.

In the second diagram, we have 3 curves namely:

- system curve

- single pump curve

- 2 pump in series curve

Also, we have points labeled 1, 2 and 3

- Point 1 represents the point that the system operates with one pump running.

- Point 2 represents the point where the flow rate of two identical pumps connected in series is twice the flow rate of a single pump.

- Point 3 is the point where the system is operating when both pumps are running.

In this case, the combined head and volume flow will move along the system curve from point 1 to point 3.

5 0
3 years ago
Example for strengthening mechanism in single-phase material A. Dispersion strengthening B. Precipitation hardening C. Fiber str
Lena [83]

Answer:

Example for strengthening mechanism in single-phase material: Strain hardening- D.

3 0
3 years ago
Read 2 more answers
Assume a factory releases a continuous flow of wastewater into a local stream, resulting in an in-stream carcinogen concentratio
AlladinOne [14]

Answer:

Calculate the individual residential lifetime cancer risk.  

Risk = Potential factor x CDI  …… (1)

Calculate the value of C  

C =  C_{o} * e^{-kt}

t = d / v

t = 150 miles / 2 mile per hrs.

t = 75 hrs

t = 75/24

t = 3.13 days

Substitute the obtained value in (2).

C = C_{o} * e^{-kt}

C = 0.72 x e^(-0.1*3.13)

C = 0.72 x 0.7313  

C = 0.526 mg/L

Substitute the obtained value in (1).

Risk = Potential factor x CDI

Risk = 0.30kg.d/mg x 0.526mg/L x 2L/d x 350day/365days

Risk = 0.3026

8 0
3 years ago
Consider a single crystal of some hypothetical metal that has the BCC crystal structure and is oriented such that a tensile stre
velikii [3]

Complete Question

Consider a single crystal of some hypothetical metal that has the BCC crystal structure and is oriented such that a tensile stress is applied along a [121] direction. If slip occurs on a (101) plane and in a [111]  direction, compute the stress at which the crystal yields if its critical resolved shear stress is 2.9 MPa.  

Answer:

The  stress is \sigma  =  10. 655 MPa

Explanation:

From the question we are told that

  The critical yield resolved shear stress is  \sigma  = 2.9Mpa

First we obtain the angle  \lambda between the slip direction [121] and  [111]

             \lambda = cos^{-1} [\frac{(u_1 u_2 + v_1 v_2 + w_1 w_2}{\sqrt{u_1^2 + v_1 ^2+ w_1^2})\sqrt{( u_2^2 + v_2^2 + w_2 ^2)} }  ]

Where u_1 ,u_2 ,v_1 , v_2 , w_1 , w_2 are the directional indices

             \lambda  =  cos ^-[ \frac{(1) (-1) + (2) (1) + (1) (1)}{\sqrt{((1)^2 +(2)^2 + (1)^2)}\sqrt{((-1)^2 + (1)^2 + (1)^2 ) }  } ]

                = cos^{-1} [\frac{2}{\sqrt{6} \sqrt{3}  } ]

                 = 61.87^0

Next is to obtain the angle \O between the direction [121] and [101]

              \O = cos^{-1} [\frac{(u_1 u_3 + v_1 v_3 + w_1 w_3}{\sqrt{u_1^2 + v_1 ^2+ w_1^2})\sqrt{( u_3^2 + v_3^2 + w_3 ^2)} }  ]

 Substituting 1 for u_1 , 2 for  v_1 , 1 for w_1 , 1 for  u_2, 0 for  v_2, and 1 for  w_2

            \O = cos^{-1} [\frac{1* 1 + 2*0 + 1*1 }{\sqrt{1^2 + 2^2 + 1^2 } \sqrt{(1^2 + 0^2 + 1^2 )}  } ]

               \O = cos^{-1} [\frac{2}{\sqrt{6} \sqrt{2}  } ]

                   = 54.74 ^o

   The stress is mathematically represented as

              \sigma = \frac{\tau_c}{cos \O cos \lambda }

                  = \frac{2.9}{cos 54.74^o cos 61.87^o}

                  =  \frac{2.9}{0.2722}

             \sigma  =  10. 655 MPa

           

       

5 0
3 years ago
34. What does the D stand for in the EVADE acronym?
rewona [7]

Answer:

Even

Vicious

Animal

Die

Equally

Explanation: im jk... but its "Designate and enforce scene control zones"

3 0
4 years ago
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