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Rus_ich [418]
4 years ago
14

Find the volume of the cone with a radius of 2 inches and a height of 5 inches

Mathematics
1 answer:
lorasvet [3.4K]4 years ago
6 0

\bf \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=2\\ h=5 \end{cases}\implies V=\cfrac{\pi (2)^2(5)}{3} \\\\\\ V=\cfrac{20\pi }{3}\implies V\approx 20.94

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inysia [295]

Answer:

Step-by-step explanation:

1). Step 4:

   x=5^{\frac{4}{3}}=(5^4)^{\frac{1}{3}}

   x=\sqrt[3]{5^4} [Since, a^{\frac{1}{3}}=\sqrt[3]{a}]

   x=\sqrt[3]{5\times 5\times 5\times 5}

   Step 5:

   x=\sqrt[3]{(5)^3\times 5}

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2). He simplified the expression by removing exponents from the given expression.

3). Let the radical equation is,

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   Step 1:

   (3x-1)^{\frac{1}{5}\times \frac{5}{1} }=2^{\frac{5}{1}}

   Step 2:

   (3x-1)=2^5

   Step 3:

   3x=32+1

   Step 4:

   x=11

4). By substituting x=11 in the original equation.

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                         =(2^5)^\frac{1}{5}

                         =2

There is no extraneous solution.

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3 years ago
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