Answer:
a) 8.13
b) 4.10
Step-by-step explanation:
Given the rate of reaction R'(t) = 2/t+1 + 1/√t+1
In order to get the total reaction R(t) to the drugs at this times, we need to first integrate the given function to get R(t)
On integrating R'(t)
∫ (2/t+1 + 1/√t+1)dt
In integration, k∫f'(x)/f(x) dx = 1/k ln(fx)+C where k is any constant.
∫ (2/t+1 + 1/√t+1)dt
= ∫ (2/t+1)dt+ ∫ (1/√t+1)dt
= 2∫ 1/t+1 dt +∫1/+(t+1)^1/2 dt
= 2ln(t+1) + 2(t+1)^1/2 + C
= 2ln(t+1) + 2√(t+1) + C
a) For total reactions from t = 1 to t = 12
When t = 1
R(1) = 2ln2 + 2√2
≈ 4.21
When t = 12
R(12) = 2ln13 + 2√13
≈ 12.34
R(12) - R(1) ≈ 12.34-4.21
≈ 8.13
Total reactions to the drugs over the period from t = 1 to t= 12 is approx 8.13.
b) For total reactions from t = 12 to t = 24
When t = 12
R(12) = 2ln13 + 2√13
≈ 12.34
When t = 24
R(24) = 2ln25 + 2√25
≈ 16.44
R(12) - R(1) ≈ 16.44-12.34
≈ 4.10
Total reactions to the drugs over the period from t = 12 to t= 24 is approx 4.10
P=2(L+W)
if given one side and the perimiter
(P/2)-L=W
(P/2)-W=L
Answer:
B. -3
Step-by-step explanation:
Starting from the y-intercept of [0, -2], you do <em>rise\</em><em>run</em><em> </em>by either moving three blocks <em>north</em><em> </em>over<em> </em>one block <em>west</em><em>,</em><em> </em>or three blocks <em>south</em><em> </em>over one block <em>east</em><em> </em>[<em>west</em> and <em>south</em> are negatives].
I am joyous to assist you anytime.
The area of the Rhombus is 162√3 sq.unit , Option A is the correct answer.
<h3>What is a Rhombus ?</h3>
A rhombus is a polygon , which has four equal sides , its diagonal bisect each other at 90 degree.
Let x be the half of the other diagonal.
tan 60 = x / 9
x = 9 tan 60
x = 9√3
Area of the Rhombus = (d1 * d2 /2 )
d1 and d2 are the length of the diagonal.
Area of the Rhombus = (9*2)(2 *9√3)/2
Area of the Rhombus =162√3 sq.unit
To know more about Rhombus
brainly.com/question/27870968
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