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ddd [48]
3 years ago
11

Sean is stacking cans of beans of the market. His shelf is 10 inches tall, 10 inches deep, and 50 inches wide. The cans are 3 in

ches tall and each has a volume of 9.42 cubic inches. How many cans will fit on the shelf?
Mathematics
1 answer:
N76 [4]3 years ago
6 0

Basically you get the volume first:

10 times 10 times 50

Which is 5,000

And we're given the cans volume already:

9.42

So what we do now is divided the area by the cans for our answer:

5,000/9.42

Which is 530.785563

So Sean can stack 530 cans of beans in his shelf.

(when rounding is is 531 cans)

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Some transportation experts claim that it is the variability of speeds, rather than the level of speeds, that is a critical fact
scZoUnD [109]

Answer:

Explained below.

Step-by-step explanation:

The claim made by an expert is that driving conditions are dangerous if the variance of speeds exceeds 75 (mph)².

(1)

The hypothesis for both the test can be defined as:

<em>H</em>₀: The variance of speeds does not exceeds 75 (mph)², i.e. <em>σ</em>² ≤ 75.

<em>Hₐ</em>: The variance of speeds exceeds 75 (mph)², i.e. <em>σ</em>² > 75.

(2)

A Chi-square test will be used to perform the test.

The significance level of the test is, <em>α</em> = 0.05.

The degrees of freedom of the test is,

df = n - 1 = 55 - 1 = 54

Compute the critical value as follows:

\chi^{2}_{\alpha, (n-1)}=\chi^{2}_{0.05, 54}=72.153

Decision rule:

If the test statistic value is more than the critical value then the null hypothesis will be rejected and vice-versa.

(3)

Compute the test statistic as follows:

\chi^{2}=\frac{(n-1)\times s^{2}}{\sigma^{2}}

    =\frac{(55-1)\times 94.7}{75}\\\\=68.184

The test statistic value is, 68.184.

Decision:

cal.\chi^{2}=68.184

The null hypothesis will not be rejected at 5% level of significance.

Conclusion:

The variance of speeds does not exceeds 75 (mph)². Thus, concluding that driving conditions are not dangerous on this highway.

7 0
3 years ago
A family built a house in a beach resort area. In 1990, the house was 430 ft from the water. With erosion, the house was 400 ft
neonofarm [45]

We develop an equation for the given situation by first writing the general equation for lines,

                                y = mx + b

Substituting to this given the values given above,

(1990)                      430 = b

(2000)                      400 = m(10) + 430

The value of m from the equation in 2000 is -3. Thus, the equation of that relates the variables is,

                              y = -3x + 430

8 0
2 years ago
What is 999+999+999+23456
ohaa [14]

Your answer is 26,453

Although I don't feel as if this is a homework question, I will still show the work.


Work:

Step 1: 999 + 999 = 1,998

Step 2: 1,998 + 999 = 2,997

Step 3: 2,997 + 23,456 = 26,453


Hope I was able to help! :)

6 0
3 years ago
Read 2 more answers
Circle X with a radius of 6 units and circle Y with a
Minchanka [31]

Answer:

The answer is C, Translate the circles so they share a common center point, and dilate circle Y by a scale factor of 3.

Step-by-step explanation:

8 0
2 years ago
Divide the following polynomial 27x^2-9a/3
ryzh [129]
<span>(27x^2-9a)/3
= 9x^2 - 3a

hope it helps</span>
6 0
2 years ago
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