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Allisa [31]
3 years ago
15

Solve this with elimination please, 3x + 6y = 6

Mathematics
2 answers:
Dafna1 [17]3 years ago
8 0
Times 2nd equation by 2
add to first equation

3x+6y=6
<u>4x-6y=8 +</u>
7x+0y=14

7x=14
divide both sides by 7
x=2

sub back

2x-3y=4
2(2)-3y=4
4-3y=4
minus 4 both sideds
-3y=0
y=0


(x,y)
(2,0)
MA_775_DIABLO [31]3 years ago
6 0
(2,0) is the correct answer
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4 percent of all cars produced on a Monday are deficient, while 3 percent of Friday's production is deficient; on all other days
neonofarm [45]

Answer:

Let the total numbers of cars be ten then the total cars produced in one week would be 50

Probability of deficient cars on Monday = 4/10

Probability of deficient cars on Tuesday =1/10

Probability of deficient cars on Wednesday = 1/10

Probability of deficient cars on Thursday = 1/10

Probability of deficient cars on Friday = 3/10

Probability ( deficient car)= 10/50 or 1/5

Probability that it produced on Monday 4/10*1/5= 4/50= 2/25= 8/100= 0.08 or 8%

Probability of deficient cars on Monday = 4/10* 12/100= 48/1000= 0.048or 4.8%

Probability of deficient cars on Tuesday =1/10 *22/100= 22/1000= 0.022 or 2.2%

Probability of deficient cars on Wednesday = 1/10*22/100=22/1000= 0.022 or 2.2%

Probability of deficient cars on Thursday = 1/10*22/100=22/1000= 0.022 or 2.2%

Probability of deficient cars on Friday = 3/10*22/100= 66/1000= 0.066 or 6.6%

8 0
3 years ago
A student council has nine officers, of which six are girls and three are boys. If two officers are chosen at random to attend a
Effectus [21]

Answer:\frac{1}{4}

Step-by-step explanation:

Given

Student council has 6 girls and 3 boys

If two person chosen at random

Probability that first officer is girl and second is a boy

=\text{Probability of choosing a girl officer}\times \text{Probability of choosing a boy officer}

=\frac{^6C_1}{^9C_1}\times \frac{^3C_1}{^8C_1}

=\frac{6}{9}\times \frac{3}{8}

=\frac{1}{4}

8 0
3 years ago
A mountain climber ascends a mountain to its peak. The peak is 12,470 ft above sea level. The climber then descends 80 ft to mee
garri49 [273]
12,390 ft above see level! I am positive and sure this is the right answer...if not please somebody correct me!
4 0
3 years ago
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Find the general solution for the differential equation \displaystyle{\left.{d}{y}\right.}+{9}{x}\ {\left.{d}{x}\right.}={0}dy+9
densk [106]

Answer:

y= CC-4.5x^2

Step-by-step explanation:

To find the general solution to the differential equation

dy + 9x dx = 0, we employ the method of separating variable as follows:

Note: { will represent the integral sign here.

Separating the variables and integrating, we have

{dy  = -{9x dx

y = -(9/2)(x^2) + CC,

where CC is the given constant of integration.

This can be rearranged/simplified to yield

y= CC-4.5x^2

6 0
3 years ago
Please help me solve this.
san4es73 [151]

the answer is x is equals to 2 or x is equal to -5 in the equation x square + 3x - 10 is equals to zero where after solving you get x square + 5 x - 2 x - 10 is equals to zero you factorise you get x (x + 5) - 2 (x + 5) is equal to zero then after solving x is equals to 2 or -5

4 0
2 years ago
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