Velocity=distance/time
Data:distance=10 Km=10 km*(0.621 miles/1 km)=6.21 miles.time=55 minutes
Velocity=6.21 miles/55 minutes=0.11290909... miles/minute≈0.113 miles/ minute
Data: distance=1 mile.velocity=0.113 miles/minute
time=distance /velocitytime=(1 mile) / (0.113 miles/ minute)=8.85668... minutes≈8.86 minutes.
Answer: D 8.86 minutes.
X=7 and x+1=8 are two consecutive integers.
Answer:
- <u><em>P(M) = 0.4</em></u>
Explanation:
<u>1. Build a two-way frequency table:</u>
To have a complete understanding of the scenary build a two-way frequency table.
Major in math No major in math Total
Major in CS
No major in CS
Total
Major in math No major in math Total
Major in CS
No major in CS
Total 200
- <u>80 plan to major in mathematics:</u>
Major in math No major in math Total
Major in CS
No major in CS
Total 80 200
- <u>100 plan to major in computer science</u>:
Major in math No major in math Total
Major in CS 100
No major in CS
Total 80 200
- <u>30 plan to pursue a double major in mathematics and computer science</u>:
Major in math No major in math Total
Major in CS 30 100
No major in CS
Total 80 200
- <u>Complete the missing numbers by subtraction</u>:
Major in math No major in math Total
Major in CS 30 70 100
No major in CS 100
Total 80 120 200
Major in math No major in math Total
Major in CS 30 70 100
No major in CS 50 50 100
Total 80 120 200
<u>2. What is P(M), the probability that a student plans to major in mathematics?</u>
- P(M) = number of students who plan to major in mathematics / number of students
For 4 copies, the total cost for preparing and printing will be the same.
Step-by-step explanation:
Let,
p be the number of pages
Company A;
Charges of preparing = $6
Charges of per page print = $2.50
A(p)= 2.50p + 6 Eqn 1
Company B;
Charges of preparing = $4
Charges of per page print = $3
B(p)= 3p + 4 Eqn 2
For equaling the cost;
A(p) = B(p)
Dividing both sides by -0.50
For 4 copies, the total cost for preparing and printing will be the same.
Keywords: Addition, division
Learn more about division at:
#LearnwithBrainly
The correct answer is:
C. 333 1/3 ml 30% solution and 166 2/3 ml of 45% solution.
The amounts of each solution as shown above should be used to make 500ml of solution with 35% acidity.
