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3 years ago

Which value is closest to the perimeter of the window

Mathematics

2 answers:

bixtya [17]3 years ago

8 0

Answer:

9.82 Is the Closest

Step-by-step explanation:

First of all, you can see its a half circle, meaning if we make it a full circle, the length of the center is 5, so the full circle's area is about 19.5-20. Now to find the area of the half circle/windows we get 9.75 - 10. The only number between that is 9.82, which should be you answer.

Have a nice day!

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Eddi Din [679]3 years ago

6 0

Answer:

9.82 feet

Step-by-step explanation:

the perimeter of the window is the circumference of a semi-circle with a diameter of 5

P = (πd)/2 (divided in half because it's only half a circle)

P ≈ 3.14(3.5) which is approx 11

11 is closest to 9.82

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Thank you an advance!

Natalka [10]

The answer is A.

I'm too tired to explain. yadayadayada

8 0

3 years ago

Read 2 more answers

A ball is thrown into the air with an upward velocity of 80ft/s. Its height H in feet after T seconds id given by the function H

pashok25 [27]

1. The function H= -16T^2+80T+5 is a parabola of the form $a x^{2} +bx+c$ , so to find the maximum height of the ball, we are going to find the y-coordinate of the vertex of the parabola. To find the y-coordinate of the vertex we are going to evaluate the function at the point $\frac{-b}{2a}$ .
From our function we can infer that $b=80$ and $a=-16$ , so the point \frac{-b}{2a} [/tex] will be $\frac{-80}{-2(16)} = \frac{5}{2}$ . Lets evaluate the function at that point:
$h=-16t^2+80t+5$
$h=-16( \frac{5}{2} )^2+80( \frac{5}{2} )+5$
$h=105$

We can conclude that the ball reaches a maximum height of 105 feet.

2. Since we now know that the maximum height the ball reaches is 105 feet, we are going to replace $h$ with 105 in our function, then we are going to solve for $t$ to find how long the ball takes to reach its maximum height:
$h=-16t^2+80t+5$
$105=-16t^{2}+80t+5$
$-16t^2+80t-100=0$
$-4(4t^{2}+20t-25)=0$
$4(2t-5)^2=0$
$2t-5=0$
$t= \frac{5}{2}$
$t=2.5$

We can conclude that the ball reaches its maximum height in 2.5 seconds.

3. Just like before, we are going to replace $h$ with 5 in our original function, then we are going to solve for $t$ to find how long will take for the ball to be caught 5 feet off the ground:
$h=-16t^2+80t+5$
$5=-16t^2+80t+5$
$-16t^{2}+80t=0$
$-16t(t-5)=0$
$t-5=0$
$t=5$

We can conclude that it takes 5 seconds for the ball to be caught 5 feet off the ground.

5 0

3 years ago

Help me please I’m not the smartest

viktelen [127]

X^2=16
x= 4 OR x=-4

The picture attached below is your answer because it’s between 4 and -4.

3 0

2 years ago

The interior angles of a triangle measures 180?<br> True or false

Ymorist [56]

it is true because al triangles angles MUST add up to 180

8 0

3 years ago

A cable 20 feet long connects the top of a flagpole to a point on the ground that is 16 feet from the base of the pole. How tall

timurjin [86]

Think of it like a triangle.

The flagpole is vertical and is at 90° to the ground. This makes a right-angle to the ground, which is flat.

Since we have two sides of the triangle already, and they are in a ratio of ?? : 16 : 20 = ?? : 4 : 5, that means that because the triangle is a right-angled triangle, the third and last side must be 3 to complete the ratio! (This is called 'Pythagoras')

Since the other sides were divided by 4 to get the simple ratio, we must multiply 3 to get the actual ratio! 3 × 4 = 12 ft tall flagpole.

3 0

3 years ago