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Alona [7]
4 years ago
9

28. A speed of a boat in still water is 11 km/hr. It can go 12 km upstream and return downstream to

Mathematics
2 answers:
AleksAgata [21]4 years ago
7 0

Answer:

5 km

Step-by-step explanation:

mel-nik [20]4 years ago
3 0

Answer:

Step-by-step explanation:

19?

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Daniel, Clarence, and Matthew split a $20.20 dinner bill so that Daniel pays half of what
Bingel [31]

Answer:

8.80$

Step-by-step explanation:

Total 20.20. 6.06 x 2=12.12. 20.20-12.12=8.80$

Mathew paid 8.80$

Clarence paid 12.12$

Daniel paid 6.06$

7 0
3 years ago
18 is what percentage of 25
pentagon [3]

Answer:

Step-by-step explanation:

72%

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3 years ago
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Which fraction is closer to 1/2 than 0 or 1?
alexandr1967 [171]

Answer:

8/12

hope this helps

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Step-by-step explanation:

7 0
3 years ago
Given: BDis a diameter<br> m 1 = 100°<br> m BC= 30°<br><br> m2 =<br><br> 30<br> 80<br> 100
skad [1K]

Answer:

∠2 = 80°

Step-by-step explanation:

Since BD is a diameter then

∠1 + ∠2 = 180°, that is

100° + ∠2 = 180° ( subtract 100° from both sides )

∠2 = 180° - 100° = 80°

4 0
4 years ago
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Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.950.950, point, 95 pro
Vinvika [58]

Answer:

40.1% probability that he will miss at least one of them

Step-by-step explanation:

For each target, there are only two possible outcomes. Either he hits it, or he does not. The probability of hitting a target is independent of other targets. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

0.95 probaiblity of hitting a target

This means that p = 0.95

10 targets

This means that n = 10

What is the probability that he will miss at least one of them?

Either he hits all the targets, or he misses at least one of them. The sum of the probabilities of these events is decimal 1. So

P(X = 10) + P(X < 10) = 1

We want P(X < 10). So

P(X < 10) = 1 - P(X = 10)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 10) = C_{10,10}.(0.95)^{10}.(0.05)^{0} = 0.5987

P(X < 10) = 1 - P(X = 10) = 1 - 0.5987 = 0.401

40.1% probability that he will miss at least one of them

7 0
3 years ago
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