The actual width of the room is 20 ft and the actual length of the room is 15 ft
Since on the scale, 2 in : 5 ft and the width of the room on the drawing is 8 in.
Let the actual width of the room is w.
The ratio of the drawing to actual width is 8 in : w
So, 2 in : 5 ft = 8 in : w
2 in/5 ft = 8 in/w
So, w = 8 in × 5 ft/2 in
w = 4 × 5 ft
w = 20 ft
Also, the length of the room on the drawing on the drawing is 6 in.
Let the actual length of the room is L.
The ratio of the drawing to actual length is 6 in : L
So, 2 in : 5 ft = 6 in : L
2 in/5 ft = 6 in/L
So, L = 6 in × 5 ft/2 in
L = 3 × 5 ft
L = 15 ft
So, the actual width of the room is 20 ft and the actual length of the room is 15 ft.
Learn more about scale drawing here:
brainly.com/question/25324744
The answer is D
alternate interior angles <span />
Answer:
9.5
Step-by-step explanation:
Using the formula
P=2(l+w)
Solving for
w=P
2﹣l=43.8
2﹣12.4≈9.5ft
Answer:
5-3í
Step-by-step explanation:
Because the root of nine is three, equaling 5-3í
We will have the following:
First, we are given the following expressions for the rectangle's length and width respectively:
&
Now, we calculate the length and width using the perimeter:
So:
Then:
So, the measurements of the length and the width are respectively 12 units and 6 units.
