<span>With the mean of 40k and standard deviation of 5k, we need to find P(x>=30k). P((30k-40k)/5k) = P(z<-2) = 1-0.0228 which is equal to 0.9772. There is a 97.72% chances that the starting salary will be at least 30k.</span>
The first one would be 120 the second one would be 68
Step-by-step explanation:
When x = -2, x + 2 = (-2) + 2 = 0.