Two cars are 190 miles apart and travel toward each other along the same road. They meet in 2 hours. One car travels 5 miles per
1 answer:
The speed of slower car is 45 mph and faster car is 50 mph.
Step-by-step explanation:
Given,
Distance covered by both cars = 190 miles
Time taken by both of them = 2 hours
Let,
x be the speed of slower car.
Speed of faster car = x+5
Combined speed = x+x+5 = 2x+5
We know that;
Distance = Speed * Time
Dividing both sides by 4
Speed of slower car = 45 miles per hour
Speed of faster car = 45+5 = 50 miles per hour
The speed of slower car is 45 mph and faster car is 50 mph.
Keywords: speed, distance
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Try this solution:
let the unknown two-digits number be 'xy'.
Then it is possible to write any two-digit number as 10x+y, where x - the tens digit and y - the unit digit.
Using the rule described above the phrase 'the tens digit of a number is twice the units digit' may be written as x=2y.
Using the same rule the phrase 'if the digits are reversed, the new number is 36 is less than the original number' may be written as (10x+y)-(10y+x)=36.
These two equations may be resolved as system of two equations:
Check: the original number is 84, the new number is 48; difference is 84-48=36.
answer: 84
let the unknown two-digits number be 'xy'.
Then it is possible to write any two-digit number as 10x+y, where x - the tens digit and y - the unit digit.
Using the rule described above the phrase 'the tens digit of a number is twice the units digit' may be written as x=2y.
Using the same rule the phrase 'if the digits are reversed, the new number is 36 is less than the original number' may be written as (10x+y)-(10y+x)=36.
These two equations may be resolved as system of two equations:
Check: the original number is 84, the new number is 48; difference is 84-48=36.
answer: 84