The vector written in its generic form is given by:
v = lvl cos theta ° i + lvl without theta ° j
Where.
lvl: magnitude of the vector
theta: angle of the vector with respect to the x axis.
For this case we have the following vector:
v = 3 cos 123 ° i + 3 without 123 ° j
Where,
lvl = 3
theta = 123 °
Answer:
The magnitude and direction angle for the vector v is:
D. 3, 123 °
Given:
Two sides of a triangle are 14 and 23.
To find:
The angle for the measures for the third side of a triangle.
Solution:
If a, b, c are three sides of a triangle, then
It is given that two sides of a triangle are 14 and 23.
Let the third side of the given triangle be c. Then, using the above inequalities, we get
...(i)
Similarly,
...(ii)
And,
...(iii)
Using (i), (ii) and (iii), we get
Therefore, the range for third side of the triangle is .
Answer:
Step-by-step explanation:
-1/5(3x-7)=18
-3x/5 + 7/5=18
-3x+7 /5=18
by cross multiplying,
-3x+7=18×5
-3x+7=90
-3x=90-7
-3x=83
x=83/-3
hope it helps it
Answer:
Step-by-step explanation:
<u>Original figure:</u> PQRTS
<u>Dilated figure:</u> P'Q'R'S'T'
<u>Take one of the corresponding sides of the figure and find the scale factor:</u>
- SR = 2, S'R' = 4
- Scale factor is 4/2 = 2
<u>The dilation rule as per above is:</u>
Correct option is A
