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Helga [31]
3 years ago
13

For what side length(s) is the area of an equilateral triangle equal to 30 cm?? Only enter the number, in centimeters, rounded t

o two decimal places. A cm ►
Mathematics
1 answer:
xenn [34]3 years ago
6 0

Answer: The sides length are 8.32 cm

Step-by-step explanation:

An equilateral triangle has all his sides of the same lenght, so we assume that the triangle has an L lenght in his sides.

The area of a triangle is Area = \frac{base * height}{2} where the base is L, the Area is 30 and an unknown height.

To determine the height, we cut the triangle in half and take one side. By simetry, one side has a base of \frac{L}{2}, a hypotenuse of L and a the unknown height.  

Then we apply the <em>Pythagoras theorem</em>, this states that <em>in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides</em>, or, hypotenuse = \sqrt{c^{2} + c^{2} } Where one c is \frac{L}{2} and the other is the height.

Then we find one of the c of the equation wich will be the height.

height = \sqrt{hypotenuse^{2}-base^{2} }

height = \sqrt{ L^{2} -\frac{L}{4} ^{2}}\\height = \sqrt{\frac{ 3L^{2}}{4} } \\\\height = \frac{\sqrt{3}L }{2}

Finally, we use the triangle area mentioned before an find the value of L.

30 = \frac{L*\frac{\sqrt{3}L }{2} }{2} \\\\L = \sqrt{\frac{120}{\sqrt{3} } } \\\\L = 8.32 cm

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