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Ostrovityanka [42]
3 years ago
8

15 POINTS PLEASE HELP!!!!!!(1/4x)^-2

Mathematics
1 answer:
kondaur [170]3 years ago
4 0

I believe its 16/x^2

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Instructions: Find the missing side lengths. Leave your answers as radicals in simplest form.
ivanzaharov [21]

Answer:

x = 6

y = 3

Step-by-step explanation:

Give triangle is a right triangle.

By applying sine ratio in the given triangle,

sin(60)° = \frac{\text{Opposite side}}{\text{Hypotenuse}}

\frac{\sqrt{3}}{2}=\frac{3\sqrt{3}}{x}

x = 6

Now we take the cosine ratio in the given triangle,

cos(60)° = \frac{\text{Adjacent side}}{\text{Hypotenuse}}

\frac{1}{2}=\frac{y}{x}

y = \frac{x}{2}

y = \frac{6}{2}=3

Therefore, x = 6 and y = 3 will be the answer.

3 0
3 years ago
PlSSS HELP IF YOU TURLY KNOW THISS
o-na [289]

Answer:

x=3  hope this helps

Step-by-step explanation:

8 0
3 years ago
–8x + 9y = –8<br> y = –8<br> substetution <br> Need fast
emmasim [6.3K]
If you substitute the -8 in for y you will get -72
You can then add the 72 to the other side and get -8x=64
Dividing by -8 to both sides to get x alone will give you x
X=-8
5 0
2 years ago
What force would have been applied to the bus from t=16 s to t=21 s? Assume the mass of the bus was 50 kg.
Svetllana [295]

Applying Newton's Second Law, it is found that the force, in Newtons, is given by:

F = 10[v(21) - v(16)]

Newton's Second Law states that Force, in Newtons, is <u>mass times acceleration</u>, that is:

F = ma

In this problem, mass of 50 kg, thus m = 50

Acceleration is <u>change in velocity divided by change in time</u>, that is:

a = \frac{\Delta_v}{\Delta_t}

In this problem, we don't know the velocities, but know that time is from 16s to 21s, thus:

\Delta_t = 21 - 16 = 5

\Delta_v = v(21) - v(16)

Thus, the force is given by:

F = ma

F = m\frac{\Delta_v}{\Delta_t}

F = 50\frac{[v(21) - v(16)]}{5}

F = 10[v(21) - v(16)]

A similar problem is given at brainly.com/question/18801986

7 0
2 years ago
All angle values for cos0=1
vagabundo [1.1K]

Cos 0° = Sin 90°

Cos 30° = Sin 60°

Cos 45° = sin 45°

Cos 60° = sin 30°

Cos 90° = sin 0°

byjus dot com

6 0
2 years ago
Read 2 more answers
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