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kkurt [141]
3 years ago
13

A sequence of two transformations that can be used to show that polygon ABCDE is congruent to polygon GFJIH

Mathematics
1 answer:
Ket [755]3 years ago
4 0

Answer:

Yes,they are congruent.

Step-by-step explanation:

We are required to make two transformations  and prove that they are congruent.

First Transformation:Now rotate the polygon FGHIJ by 90° about the axis parallel to x-axis and passinfg through the vertex I.You can observe that the sides are of same length AB=GF=2 units.

Second Transformation: Keeping the polygon ABCDE constant shift the centre of polygon FGHIJ to the centre of polygon ABCDE you will observe thta they exactly overlap on each other hence they are congruent with each other.

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On one map of a town, the scale from the town to the map is 12mi:
Yuri [45]

The distance between the school and the library is less. Then the library is closer to school.

<h3>What is dilation?</h3>

Dilation is the process of increasing the size of an item without affecting its form. Depending on the scale factor, the object's size can be raised or lowered.

There is no effect of dilation on the angle.

On one map of a town, the scale from the town to the map is 12mi:3cm.

The school is 2.5cm from the grocery store on this map.

Then the distance between the school and the grocery store will be

⇒ (12 / 3) x 2.5

⇒ 10 miles

On a different map of the same town, the scale from the town to the make is 12mi: 2cm.

The school is 1.5cm from the library on that map.

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Then the library is closer to school.

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2 years ago
I really need help please answer
belka [17]

Answer: Choice B) between 6:48 AM and 5:12 PM

=========================================================

Explanation:

I've seen this problem before, and the first part states that if the temperature is above 25 degrees C, then the air conditioner turns on to start cooling the castle.

We want to find values of t that satisfy f(t) > 25

This is the same as trying to solve f(t) - 25 > 0

So we have,

f(t) = 24 - 5\cos\left(\frac{\pi}{12}t\right)\\\\   f(t)-25 = 24 - 5\cos\left(\frac{\pi}{12}t\right)-25\\\\   f(t)-25 = -1 - 5\cos\left(\frac{\pi}{12}t\right)\\\\   f(t)-25 > 0\\\\ -1 - 5\cos\left(\frac{\pi}{12}t\right) > 0\\\\

To solve this inequality, we can graph using Desmos as I've done so below. See the attached image.

Note how I used x in place of t. This is because the graphing calculator graphs (x,y) coordinates.

Furthermore, note how I marked the two points (6.769, 0) and (17.231, 0)

Between these two points is when the curve is above the x axis, when f(t) > 25 is true. This is when the temperature is above 25 degrees C, and when the air conditioner is working.

When t = 6.769, this means that roughly 6.769 hours have passed since midnight which means we're somewhere between 6 am and 7 am. The only value that works from the answer choices is 6:48 AM.

Note how 0.769*60 = 46.14 is fairly close to 48. This error is likely due to how things are rounded.

Then focusing on the point  (17.231, 0) means that t = 17.231. So 17.231 hours have elapsed since midnight and we're now at roughly 1700 hours

1700 hours in military time = 17-12 = 5 pm

The time value t = 17.231 is between 5 pm and 6 pm. The only thing that works is 5:12 pm.

We can then note how 0.231*60 = 13.86 which is also probably due to rounding error (it's fairly close to 12 though).

--------------------------

In short, we found the function for f(t)-25 and graphed it as shown below. The two points (6.769, 0) and (17.231, 0) help us see when the AC is turned on, which is roughly between 6:48 AM and 5:12 PM. This seems like a reasonable time for the AC to be operational. Something like between 5:12 PM and 6:48 AM seems like a bad idea because the AC would be working mostly at night, instead of during the day.

Anything beyond t = 24 represents the next day, which is when the cycle starts all over again. So we only need to focus on the window from t = 0 to t = 24. Specifically, the portion of the f(t)-25 curve that is above the x axis.

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