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ICE Princess25 [194]
3 years ago
10

HELP ME PLEASE

Mathematics
1 answer:
dsp733 years ago
3 0
Preyton took longer so he was slower. Now, we calculate the average speeds of both:
Preyton: 150 / 3 = 50 mph
Bryson: 150 / 2.5. = 60 mph

Therefore, Bryson travelled 10 mph faster than Preyton
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sasho [114]

Answer:

C. Test for Goodness-of-fit.

Step-by-step explanation:

C. Test for Goodness-of-fit would be most appropriate for the given situation.

A. Test Of  Homogeneity.

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B. Test for Independence.

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C. Test for Goodness-of-fit.

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