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damaskus [11]
2 years ago
10

Encik Basra’s age is four times his child’s age. 4 years ago, Encik Basri’s age is six times his child age. Find the age of Enci

k Basri’s child now.
Mathematics
1 answer:
Luden [163]2 years ago
4 0

Answer:

4 + 6 = 10 * 4 =40

Step-by-step explanation:

sana makatulong

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Mathews usually makes the 100 km journey to visit his family. The trip involves three separate stages:
12345 [234]

Answer:

1 . Total time = 1 hr 55 minutes

2 Distance = 121 km

Step-by-step explanation:

Mattew journey

stage a

Distance = 20km

Speed = 30km/h

Time = distance/speed

Time = 20/30

Time = 2/3 h

Time = 40 minutes

Stage b

Distance = 50 I'm

Speed = 100 km/h

Time = distance/speed

Time = 50/100

Time = 0.5 h

Time = 30 minutes

Stage c

Distance = 30 km

Speed = 40 km/h

Time = distance/speed

Time = 30/40

Time = 3/4 h

Time = 45 minutes.

Total time taken =( 40 + 30 + 45 ) minutes

Total time = 115 minutes

Total time = 1 hr 55 minutes

2.

Speed =60 km/h

Time= 6 minutes + x

And x = 1 hr 55 minutes

Time = 1 hr 55 minutes + 6 minutes

Time = 2 hr 1 minute

Time = 2.01666667 hr

Distance covered = speed * time

Distance = 60*2.016667

Distance = 121 km

3 0
3 years ago
Giving brainiest please help
sleet_krkn [62]
50000000 is the answer
5 0
2 years ago
Read 2 more answers
Plz help me find 100th term!!!it is on the BOTTOM!
Whitepunk [10]

Answer:

that's a hundred and three because n which is the variable * 100 + 3 equals 103

7 0
3 years ago
Melissa got 18 out of 20 on a math quiz. Tom got 85% on the quiz. Whose mark was greater?
Zina [86]

Answer:

tom =  \frac{85}{100}  \times 20 \\  = 17 \: questions

Melissa had a greater mark.

4 0
2 years ago
Read 2 more answers
Find the directional derivative of f(x,y,z)=z3−x2yf(x,y,z)=z3−x2y at the point (−5,5,2)(−5,5,2) in the direction of the vector v
olga_2 [115]

We are given

f=z^3 -x^2y

Firstly, we can find gradient

so, we will find partial derivatives

f_x=0 -2xy

f_x=-2xy

f_y=0 -x^2

f_y=-x^2

f_z=3z^2

now, we can plug point (-5,5,2)

f_x=-2*-5*5=50

f_y=-(-5)^2=-25

f_z=3(2)^2=12

so, gradient will be

gradf=(50,-25,12)

now, we are given that

it is in direction of v=⟨−3,2,−4⟩

so, we will find it's unit vector

|v|=\sqrt{(-3)^2+(2)^2+(-4)^2}

|v|=\sqrt{29}

now, we can find unit vector

v'=(\frac{-3}{\sqrt{29} } , \frac{2}{\sqrt{29} } , \frac{-4}{\sqrt{29} })

now, we can find dot product to find direction of the vector

dir=(gradf) \cdot (v')

now, we can plug values

dir=(50,-25,12) \cdot (\frac{-3}{\sqrt{29} } , \frac{2}{\sqrt{29} } , \frac{-4}{\sqrt{29} })

dir=(-\frac{150}{\sqrt{29} } - \frac{50}{\sqrt{29} } - \frac{48}{\sqrt{29} })

dir=-\frac{248\sqrt{29}}{29}.............Answer



7 0
3 years ago
Read 2 more answers
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