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lianna [129]
3 years ago
10

( -5.5x +3)-2(-2.75x -2.5 =

Mathematics
2 answers:
Jobisdone [24]3 years ago
7 0
(-5,5x+3)-2(-2,75x - 2,5)(-5,5x+3)(5,5x+5)=-30,25x² - 27,5x + 16 ,5x +15=-30,25x² - 11x+15

Illusion [34]3 years ago
4 0
(-5,5x+3)-2(-2,75x - 2,5)
(-5,5x+3)(5,5x+5)
=-30,25x² - 27,5x + 16 ,5x +15
=-30,25x² - 11x+15
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Pls help me this is due today
alex41 [277]

Answer:

Option 1

Step-by-step explanation:

The shaded area is 2/3 and it is divided into 1/9 pieces. So, 2/3 divided by 1/9 which equals 6 pieces. The only equation that matches this is option 1.

4 0
2 years ago
Does anyone know what the code is Ive been stuck on this for like ever.
timama [110]

Answer:

Binary code

Step-by-step explanation:

Code is a word or a symbol which is not disclosed to everyone and is considered as secretive. There are various codes which are required to run a software in order to minimize the risk of piracy. These codes are binary codes or java codes. These are complex so that not everyone can crack it.

3 0
3 years ago
1. Solve -35 = -5x ........................
Valentin [98]

Answer:

x = 7.

Step-by-step explanation:

-5x = -35

x = -35 / -5 = 7.

3 0
3 years ago
Read 2 more answers
express the numbers eight, fifteen and seventeen in base 2. I have forgotten how to do the base 2 question.
saw5 [17]
The quickest way for converting small numbers like this to binary would probably be to find the closest power of 2, then add/subtract intermediate powers of 2 as needed.

Converting 8 is immediate, since it's already a power of 2:

8=2^3\implies 8_{10}=1000_2

Converting 15 and 17 is also pretty easy if you're familiar with the rules of arithmetic in binary.

15=16-1=2^4-2^0\implies 15_{10}=16_{10}-1_{10}=10000_2-1_2=1111_2

17=16+1=2^4+2^0\implies 17_{10}=10000_2+1_2=10001_2
6 0
3 years ago
An ordinary (fair) coin is tossed 3 times. Outcomes are thus triples of "heads" () and "tails" () which we write , , etc. For ea
boyakko [2]

Answer:

Some details are missing

Step-by-step explanation:

An ordinary (fair) coin is tossed 3 times. Outcomes are thus triples of "heads" (h) and "tails) (t) which we write hth, ttt, etc. For each outcome, let R be the random variable counting the number of heads in each outcome. For example, if the outcome is hht, then R(hht) = 2. Suppose that the random variable X is defined in terms of R as follows: X = 2R² - 6R - 1. The values of X are thus:

Outcome: || Value of X

tht || -5

thh || -5

hth || -5

htt || -5

hhh || -1

tth || -5

hht || -5

ttt || -1

Calculate the probability distribution function of X, i.e. the function Px (x). First, fill in the first row with the values of X. Then fill in the appropriate probabilities in the second row.

Solution

To calculate the probability distribution function of X.

We have to observe the total outcomes to check the number of "Heads (h) " in each outcome.

The first, fourth and, sixth outcome has 1 head (h)

The second, third and seventh outcome has 2 head (hh)

The fifth outcome has 3 head (hhh)

The eight outcome has 0 appearance of h

We then solve the probability of each occurrence

i.e. The probability of having h, hh, hhh and no occurrence of h

This will be represented as follows

P(h=0)

P(h=1)

P(h=2)

P(h=3)

In a coin, the probability of getting a head = ½ and the probability of getting a tail = ½ in 1 toss

Using the following formula

P(X=x) = nCr a^r * b ^ (n-r)

Where n represents total number of toss = 3

r represents number of occurrence

a represents getting a head = ½

b represents probability of getting a tail = ½

1. For h = 0

P(h=0) = 3C0 * ½^0 * ½³

P(h=0) = 1 * 1 * ⅛

P(h=0) = ⅛

2. For h = 1

P(h=1) = 3C1 * ½^1 * ½²

P(h=1) = 3 * ½ * ¼

P(h=1) = ⅜

3. P(h=2) = 3C2 * ½² * ½^1

P(h=2) = 3 * ¼ * ½

P(h=2) = ⅜

4.P(h=3) = 3C3 * ½³ * ½^0

P(h=0) = 1 * ⅛ * 1

P(h=0) = ⅛

It should be noted that when X is -5, h is either 1 or 2 and P(X) = ⅜

When X is -1, h is either 0 or 3 and P(X) = ⅛

The probability distribution function of X is as follows

Values of X || P(x)

-5 || ⅜

1 || ⅛

6 0
3 years ago
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