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3 years ago

after walking 15 mins zacharys treadmill displayed 120 calories burned, at this rate how many calories can zach burn in 65 mins

Mathematics

1 answer:

Monica [59]3 years ago

3 0

Step-by-step explanation:

520 calories

15 mins = 120 calories

65 mins = 65/15 × 120

= 520 calories

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Find the quotient of: (-20xyz) (5zy)

vichka [17]

Answer:

the answer would be -4x

Step-by-step explanation:

dividing (-20xyz) by (5zy) = 3

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3 years ago

Can you help me solve for x?

sergiy2304 [10]

Answer:

x = 12

Step-by-step explanation:

The exterior angle of a triangle is equal to the sum of the opposite interior angles

10x-10 = 60 +4x+2

Combine like terms

10x-10 = 62+4x

Subtract 4x from each side

10x-4x -10 = 62 +4x-4x

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Add 10 to each side

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Step-by-step explanation:

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2 years ago

A distance AB is observed repeatedly using the same equipment and procedures, and the results, in meters, are listed below: 67.4

skad [1K]

Answer:

a) $\bar X =\frac{67.401+67.400+67.402+67.396+67.406+67.401+67.396+67.401+67.405+67.404}{10}=67.401$

b) The sample deviation is calculated from the following formula:

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And for this case after replace the values and with the sample mean already calculated we got:

$s=0.0036$

If we assume that the data represent a population then the standard deviation would be given by:

$\sigma=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n}}$

And then the deviation would be:

$\sigma =0.00319$

Step-by-step explanation:

For this case we have the following dataset:

67.401, 67.400, 67.402, 67.396, 67.406, 67.401, 67.396, 67.401, 67.405, and 67.404

Part a: Determine the most probable value.

For this case the most probably value would be the sample mean given by this formula:

$\bar X =\frac{\sum_{i=1}^n X_i}{n}$

And if we replace we got:

$\bar X =\frac{67.401+67.400+67.402+67.396+67.406+67.401+67.396+67.401+67.405+67.404}{10}=67.401$

Part b: Determine the standard deviation

The sample deviation is calculated from the following formula:

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And for this case after replace the values and with the sample mean already calculated we got:

$s=0.0036$

If we assume that the data represent a population then the standard deviation would be given by:

$\sigma=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n}}$

And then the deviation would be:

$\sigma =0.00319$

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3 years ago