What word? Be more specific please
The equation of a cirecle with radius r and center at (h,k) is
(x-h)^2+(y-k)^2=r^2
r=10
center=(-2,-4)
(x+2)^2+(y+4)^2=10^2
(x+2)^2+(y+4)^2=100
(x,y)
sub given points (or use TI) and see if you get a true statmeent
A is on it
answer is A
Answer:
For number 1, you draw a line to the middle graph
For number 2, you draw a line to the bottom graph
For number 3, you draw a line to the top graph.
Step-by-step explanation:
To figure out where the graph goes, you only need to know if the point is on the graph. For the top graph, you know that the point 2,2 is on the graph so that means one part of the graph has to be 2 and 2. The x has to equal to and the y is equal 2. Therefore, you have to draw it to the bottom graph.
If this has helped you, please mark this answer as brainliest
Answer:
(f⁻¹)'(b) = 1/f'(f⁻¹(b)) = 1/f'(a)
Step-by-step explanation:
The function f⁻¹(x) is the reflection of the function f(x) across the line y=x. Every point (a, b) that is on the graph of f(x) is reflected to be a point (b, a) on the graph of f⁻¹(x).
Any line with slope m reflected across the line y=x will have slope 1/m. (x and y are interchanged, so m=∆y/∆x becomes ∆x/∆y=1/m) Since f'(x) is the slope of the tangent line at (x, f(x)), 1/f'(x) will be the slope of the tangent line at (f(x), x).
Replacing x with f⁻¹(x) in the above relation, you get ...
... (f⁻¹)'(x) = 1/f'(f⁻¹(x)) will be the slope at (x, f⁻¹(x))
Putting your given values in this relation, you get
... (f⁻¹)'(b) = 1/f'(f⁻¹(b)) = 1/f'(a)
Answer:
-6
Step-by-step explanation:
-x/3=2
Multiply both sides by 3:
-x=6
Divide both sides by -1:
x=-6
Hope this helps!