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damaskus [11]
3 years ago
10

To form 3 adjacent squares (as in the figure), 10 toothpicks are required. How many toothpicks are required to form 50 adjacent

squares?
Mathematics
1 answer:
nalin [4]3 years ago
6 0
3/10 =50/x First multiply 50x10 then divide that number by 3 to get the answer
You might be interested in
−15x + 60 ≤ 105 AND 14x + 11 ≤ −31
almond37 [142]
Answer:

1. -15x + 60 <= 105 2. 14x + 11 <= - 31

Step-by-step explanation:
1. x> = - 3
2. x <= - 3

Isolate the variable by dividing each side by factors that don't contain the variable
5 0
3 years ago
Read 2 more answers
Question 7 options:<br><br> 2/3<br><br><br> 2<br><br><br> 8/27<br><br><br> 3
topjm [15]

Answer:

2/3

Step-by-step explanation:

If 2/3 · x= 4/9 then 4/9 ÷ 2/3= x

KCF (Keep Change Flip)

Keep 4/9

4/9 ÷ 2/3

Change from division to multiplication

4/9 · 2/3

Flip 2/3 to 3/2

4/9 · 3/2

Multiply 4 · 3= 12

Multiply 9 · 2= 18

Simplify

12 ÷ 6= 2

18 ÷ 6= 3

x=2/3

5 0
3 years ago
Given: Point C is the midpoint of AB¯¯¯¯¯.
suter [353]

Answer:

See proof below

Step-by-step explanation:

If C is the midpoint of AB, then AC = CB

Given

AC=7x−10;

CB=3x+10

Then 7x - 10= 3x+10

Add 10 to both sides

7x-10+10 = 3x +10+10

7x = 3x + 20

7x - 3x   = 10+10

4x = 20

x = 20/4

x = 5

Get AC

AC = 7x - 10

AC= 7(5) - 10

AC = 35-10

AC = 25 (Proved)

3 0
2 years ago
Kesha threw her baton up in the air from the marching band platform during practice. The equation h(t) = −16t² + 54t + 40 gives
lapo4ka [179]

Answer:

a) 40 feet

b) 54 ft/min

c) 4 mins

Step-by-step explanation:

Solution:-

- Kesha models the height ( h ) of the baton from the ground level but thrown from a platform of height hi.

- The function h ( t ) is modeled to follow a quadratic - parabolic path mathematically expressed as:

                           h ( t ) = −16t² + 54t + 40

Which gives the height of the baton from ground at time t mins.

- The initial point is of the height of the platform which is at a height of ( hi ) from the ground level.

- So the initial condition is expressed by time = 0 mins, the height of the baton h ( t ) would be:

                         h ( 0 ) = hi = -16*(0)^2 + 54*0 + 40

                         h ( 0 ) = hi = 0 + 0 + 40 = 40 feet

Answer: The height of the platform hi is 40 feet.

- The speed ( v ) during the parabolic path of the baton also varies with time t.

- The function of speed ( v ) with respect to time ( t ) can be determined by taking the derivative of displacement of baton from ground with respect to time t mins.

                        v ( t ) = dh / dt

                        v ( t )= d ( −16t² + 54t + 40 ) / dt

                        v ( t )= -2*(16)*t + 54

                        v ( t )= -32t + 54

- The velocity with which Kesha threw the baton is represented by tim t = 0 mins.

Hence,

                        v ( 0 ) = vi = -32*( 0 ) + 54

                        v ( 0 ) = vi = 54 ft / min

Answer: Kesha threw te baton with an initial speed of vo = 54 ft/min

- The baton reaches is maximum height h_max and comes down when all the kinetic energy is converted to potential energy. The baton starts to come down and cross the platform height hi = 40 feet and hits the ground.

- The height of the ball at ground is zero. Hence,

                     h ( t ) = 0

                     0 = −16t² + 54t + 40

                     0 = -8t^2 + 27t + 20

- Use the quadratic formula to solve the quadratic equation:

                     

                    t = \frac{27+/-\sqrt{27^2 - 4*8*(-20)} }{2*8}\\\\t = \frac{27+/-\sqrt{1369} }{16}\\\\t = \frac{27+/-37 }{16}\\\\t =  \frac{27 + 37}{16} \\\\t = 4

Answer: The time taken for the baton to hit the ground is t = 4 mins

3 0
3 years ago
A household aquarium tank in the shape of a rectangular prism has a base length of 242424 inches (\text{in})(in)(, start text, i
mars1129 [50]

Answer:

The absolute change in the height of the water is 9.5 inches

Step-by-step explanation:

Given

l =24in --- length

w = 15in --- width

h =12in --- height

V_1 = 900in^3 --- the volume removed

Required

The absolute change in the height of the water

First, calculate the base area (b):

b = l * w

b =24in * 15in

b =360in^2

The height of the water that was removed is:

<em />H = \frac{V_1}{b}<em> i.e. the volume of the water removed divided by the base area</em>

H = \frac{900in^3}{360in^2}

H = \frac{900in}{360}

H = 2.5in

The absolute change in height is:

\triangle H = |h - H|

\triangle H = |12in - 2.5in|

\triangle H = |9.5in|

\triangle H = 9.5in

8 0
2 years ago
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