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2 years ago

Which expression is equivalent to 3 square root of 125x6y15z3?

1 answer:

5 0

Assuming this expression is: $\sqrt[3]{125x^6y^{15}z^3}$ , we can take the cube roots of each of the individual terms 125, $x^6, y^{15}, z^3$ . The cube root of 125 is 5, while the cube root of the exponents is simplified by dividing each exponent by 3. This results in the answer of: $5x^{\frac{6}{3}}y^{\frac{15}{3}}z^{\frac{3}{3}} = 5x^2y^5z$

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maria buys 8 1/3 pounds of beef to make tacos for a party .She uses 5/9 pound of beef for each toco. how many tacos can maria ma

Olin [163]

Just do 8 1/3 divided by 5/9 or

25/3 / 5/9

25/3 * 9/5 = 5/1 * 3/1 = 15

So 15 tacos

* = times

/ = divided by

7 0

2 years ago

Determine if the given mapping phi is a homomorphism on the given groups. If so, identify its kernel and whether or not the mapp

shtirl [24]

Answer:

(a) No. (b)Yes. (c)Yes. (d)Yes.

Step-by-step explanation:

(a) If $\phi: G \longrightarrow G$ is an homomorphism, then it must hold

that $b^{-1}a^{-1}=(ab)^{-1}=\phi(ab)=\phi(a)\phi(b)=a^{-1}b^{-1}$ ,

but the last statement is true if and only if G is abelian.

(b) Since G is abelian, it holds that

$\phi(a)\phi(b)=a^nb^n=(ab)^{n}=\phi(ab)$

which tells us that $\phi$ is a homorphism. The kernel of $\phi$

is the set of elements g in G such that $g^{n}=1$ . However,

$\phi$ is not necessarily 1-1 or onto, if $G=\mathbb{Z}_6$ and

n=3, we have

$kern(\phi)=\{0,2,4\} \quad \text{and} \quad\\\\Im(\phi)=\{0,3\}$

(c) If $z_1,z_2 \in \mathbb{C}^{\times}$ remeber that

$|z_1 \cdot z_2|=|z_1|\cdot|z_2|$ , which tells us that $\phi$ is a

homomorphism. In this case

$kern(\phi)=\{\quad z\in\mathbb{C} \quad | \quad |z|=1 \}$ , if we write a

complex number as $z=x+iy$ , then $|z|=x^2+y^2$ , which tells

us that $kern(\phi)$ is the unit circle. Moreover, since

$kern(\phi) \neq \{1\}$ the mapping is not 1-1, also if we take a negative

real number, it is not in the image of $\phi$ , which tells us that

$\phi$ is not surjective.

(d) Remember that $e^{ix}=\cos(x)+i\sin(x)$ , using this, it holds that

$\phi(x+y)=e^{i(x+y)}=e^{ix}e^{iy}=\phi(x)\phi(x)$

which tells us that $\phi$ is a homomorphism. By computing we see

that $kern(\phi)=\{2 \pi n| \quad n \in \mathbb{Z} \}$ and

$Im(\phi)$ is the unit circle, hence $\phi$ is neither injective nor

surjective.

7 0

3 years ago

Which fraction is equal to 5 3/4 ? 12/4 15/4 23/4 53/4

34kurt

23/4 i swear that’s the answer hope it helps

7 0

3 years ago

Read 2 more answers

Tyler and Elena are on the cross country. Tyler's distance and times for a training run are shown on the graph.

Karolina [17]

Answer:

shown

Step-by-step explanation:

This is the link to the same question i think with a answer, im not good at these types of math but hopefully this helps you guys out! brainly.com/question/13982030

8 0

2 years ago

Helppp please this is urgent :) thank you

larisa [96]

The slope would be -5/4 or -1.25 because the y-intercept is (0,5) and x-intercept is (4,0), thus giving y = 5 - (5 x)\/4

6 0

3 years ago