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3 years ago

If f(x)= 3x-1 and g(x)= x+2, find (f-g)(x).

Mathematics

2 answers:

mestny [16]3 years ago

8 0

F(x) = 3x-1
g(x) = x+2

Find (f-g)(x), this means we need to subtract g from x.

(3x-1) - (x+2)

Subtract the like terms:

3x -x = 2x

-1 -2 = -3

Combine them to get 2x-3

The answer is A.

Vladimir [108]3 years ago

6 0

Answer:

Option A.

Step-by-step explanation:

The given functions are

$f(x)=3x-1$

$g(x)=x+2$

we need to find the function (f-g)(x).

Using the composition of functions the subtraction of two functions is defined as

$(f-g)(x)=f(x)-g(x)$

Substitute the given values of functions f(x) and g(x).

$(f-g)(x)=(3x-1)-(x+2)$

$(f-g)(x)=3x-1-x-2$

On combining line terms we get

$(f-g)(x)=(3x-x)+(-1-2)$

$(f-g)(x)=2x-3$

Therefore, the correct option is A.

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2 years ago

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vekshin1

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3 years ago

Christian and Yong had some stickers in the ratio 2:3. After Yong gave Christian 15 stickers, the ratio became 5:7. What was the

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step-by-step explanation:

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2 years ago

4/5 divided by 1/3 plus 1/5 minus 3/5

r-ruslan [8.4K]

Answer:

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12$

Step-by-step explanation:

Considering the expression

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}$

Solution Steps:

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}$

$\mathrm{Combine\:the\:fractions\:}\frac{1}{5}-\frac{3}{5}:\quad -\frac{2}{5}$

$=\frac{\frac{4}{5}}{\frac{1}{3}-\frac{2}{5}}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{\frac{b}{c}}{a}=\frac{b}{c\:\cdot \:a}$

$=\frac{4}{5\left(\frac{1}{3}-\frac{2}{5}\right)}$

join $\frac{1}{3}-\frac{2}{5}:\quad -\frac{1}{15}$

$=\frac{4}{5\left(-\frac{1}{15}\right)}$

$\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a$

$=\frac{4}{-5\cdot \frac{1}{15}}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{-b}=-\frac{a}{b}$

$=-\frac{4}{5\cdot \frac{1}{15}}$

$\mathrm{Multiply\:}5\cdot \frac{1}{15}\::\quad \frac{1}{3}$

$=-\frac{4}{\frac{1}{3}}$

$\mathrm{Simplify}\:\frac{4}{\frac{1}{3}}:\quad \frac{12}{1}$

$=-\frac{12}{1}$

$\mathrm{Apply\:rule}\:\frac{a}{1}=a$

$=-12$

Therefore

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12$

4 0

2 years ago