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3 years ago

About what percent of men aged 25 to 34 are less than 70 inches tall

Mathematics

2 answers:

Fantom [35]3 years ago

7 0

Are there no answer choices?

ira [324]3 years ago

5 0

Answer: 39% is correct on grad point / connexus

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Tom Johnson worked 32 hours this week for $9.25 per hour. What is Tom’s gross pay for the week?

Dominik [7]

Answer:

296 dollars

Step-by-step explanation:

5 0

3 years ago

PLEASE HELP<br><br> Graph the ordered pairs for y = 3x + 3 using r = {-2, 1, 2}.

Fed [463]

9514 1404 393

Answer:

(-2, -3), (1, 6), (2, 9) are plotted in the attached graph

Step-by-step explanation:

For x = -2, y = 3(-2) +3 = -3. The ordered pair is (-2, -3).

For x = 1, y = 3(1) +3 = 6. The ordered pair is (1, 6).

For x = 2, y = 3(2) +3 = 9. The ordered pair is (2, 9).

The graph is attached.

5 0

3 years ago

Read 2 more answers

PLS HELP! URGENT!!!! A circular flower bed is 20 m in diameter and has a circular sidewalk around it that is 3 m wide. Find the

krok68 [10]

Answer: Area of sidewalk is 217m²

Step-by-step explanation:

The formula for determining the area of a circle is expressed as

Area = πr²

Where

r represents the radius of the circle

π is a constant whose value is 3.14

A circular flower bed is 20 meters in diameter.

radius = diameter/2 = 20/2 = 10 meters

Area of the flower bed = 3.14 × 10²

= 314m²

The circular flower bed has a circular sidewalk around it that is 3 meters wide. This means that the total diameter would be

3 + 20 + 3 = 26m

Radius = 26!2 = 13m

Total area = 3.14 × 13² = 530.66m²

Therefore, area of the sidewalk is

530.66 - 314 = 216.66

The area of sidewalk is 217m² to the nearest whole number

6 0

3 years ago

Find the solution of the given initial value problem:<br><br> y''- y = 0, y(0) = 2, y'(0) = -1/2

igor_vitrenko [27]

Answer: The required solution of the given IVP is

$y(x)=\dfrac{3}{4}e^x+\dfrac{5}{4}e^{-x}.$

Step-by-step explanation: We are given to find the solution of the following initial value problem :

$y^{\prime\prime}-y=0,~~~y(0)=2,~~y^\prime(0)=-\dfrac{1}{2}.$

Let $y=e^{mx}$ be an auxiliary solution of the given differential equation.

Then, we have

$y^\prime=me^{mx},~~~~~y^{\prime\prime}=m^2e^{mx}.$

Substituting these values in the given differential equation, we have

$m^2e^{mx}-e^{mx}=0\\\\\Rightarrow (m^2-1)e^{mx}=0\\\\\Rightarrow m^2-1=0~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mx}\neq0]\\\\\Rightarrow m^2=1\\\\\Rightarrow m=\pm1.$

So, the general solution of the given equation is

$y(x)=Ae^x+Be^{-x},$ where A and B are constants.

This gives, after differentiating with respect to x that

$y^\prime(x)=Ae^x-Be^{-x}.$

The given conditions implies that

$y(0)=2\\\\\Rightarrow A+B=2~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

and

$y^\prime(0)=-\dfrac{1}{2}\\\\\\\Rightarrow A-B=-\dfrac{1}{2}~~~~~~~~~~~~~~~~~~~~~~~~(ii)$

Adding equations (i) and (ii), we get

$2A=2-\dfrac{1}{2}\\\\\\\Rightarrow 2A=\dfrac{3}{2}\\\\\\\Rightarrow A=\dfrac{3}{4}.$

From equation (i), we get

$\dfrac{3}{4}+B=2\\\\\\\Rightarrow B=2-\dfrac{3}{4}\\\\\\\Rightarrow B=\dfrac{5}{4}.$

Substituting the values of A and B in the general solution, we get

$y(x)=\dfrac{3}{4}e^x+\dfrac{5}{4}e^{-x}.$

Thus, the required solution of the given IVP is

$y(x)=\dfrac{3}{4}e^x+\dfrac{5}{4}e^{-x}.$

4 0

3 years ago

Can you tell me what the equation is in standard form ? Y - 9 =2(x+9)

AysviL [449]

Answer:

2x-y=-27 in standard from

Step-by-step explanation:

8 0

3 years ago