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Flauer [41]
3 years ago
5

How much should you invest at 4% simple interest in order to earn $50 interest in 6 months

Mathematics
1 answer:
LenaWriter [7]3 years ago
4 0
Simple interest formula
Interest = Pit = $50
P=principal (initial investment)
i=annual interest rate = 0.04
t=time in years = 6 months = 0.5 years

Substitute values,
$50 = P*0.04*0.5 
Solve for P
P=$50/(0.04*0.5)=$2500


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Solve showing work <br>please help<br>don't understand :(
Viktor [21]
This is actually a very simple problem when you understand how to do it.

First, I would add the 12 to both sides. 
Equation would now look like this x/6=24 
Then I would do the inverse (opposite) of division which is multiplication. 
So multiply 6 to both sides so we can get the x alone. 6*12=144
Now x is alone, and X = 144. 
Feel free to ask me questions!
8 0
3 years ago
How much of the initial mass remains after 80 years? (Round your answer to three decimal places.)
aleksandr82 [10.1K]

Given

y=11(\frac{1}{2})^{\frac{t}{30}}

When t = 80

We substitute for t

y=11(\frac{1}{2})\frac{}{}^{\frac{80}{30}}

Simplify

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Simplify further

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The final answer

4 0
1 year ago
A forestry company hopes to generate credits from the carbon sequestered in its plantations.The equation describing the forest w
Dmitry [639]

Answer:

Explanation:

Given:

The equation describing the forest wood biomass per hectare as a function of plantation age t is:

y(t) = 5 + 0.005t^2 + 0.024t^3 − 0.0045t^4

The equation that describes the annual growth in wood biomass is:

y ′ (t) = 0.01t + 0.072t^2 - 0.018t^3

To find:

a) The year the annual growth achieved its highest possible value

b) when does y ′ (t) achieve its highest value?

a)

To determine the year the highest possible value was achieved, we will set the derivative y'(t) to zero. The values of t will be substituted into the second derivative to get the highest value

\begin{gathered} 0\text{ = 0.01t + 0.072t}^2\text{ - 0.018t}^3 \\ using\text{ a graphing tool,} \\ t\text{  = -0.1343} \\ \text{t = 0} \\ t\text{ = 4.1343} \\  \\ Since\text{ we can't have time as a negative value, t = 0 or t = 4.1343} \end{gathered}\begin{gathered} To\text{ ascertain which is the maximum, we take a second derivative} \\ y^{\prime}\text{'\lparen t\rparen = 0.01 + 0.144t - 0.054t}^2 \\  \\ substitute\text{ t = 0 and t = 4.13 respectively} \\ when\text{ t = 0 } \\ y^{\prime}\text{'\lparen t\rparen= 0.01 + 0.144\lparen0\rparen - 0.054\lparen0\rparen}^2 \\ y^{\prime}\text{'\lparen t\rparen= 0.01 + 0 - 0} \\ y^{\prime}\text{'\lparen t\rparen= 0.01 > 0} \\  \\ y^{\prime}\text{'\lparen t\rparen= 0.01 + 0.144\lparen4.13\rparen - 0.054\lparen4.13\rparen}^2 \\ y^{\prime}\text{'\lparen t\rparen= -0.316 < 0} \\  \\ if\text{ }y^{\prime}\text{'\lparen t\rparen > 0 , then it is minimum, } \\ if\text{ }y^{\prime}\text{'\lparen t\rparen < 0, then it is maximum} \end{gathered}

SInce t = 4.13, gives y ′' (t) = -0.316 (< 0). This makes it the maximum value of t

The year the annual growth achieved its highest possible value to the nearest whole number will be

year 4

b) y ′ (t) will achieve its highest value, when we substitute the value of t that gives into the initial function.

Initial function: y(t) = 5 + 0.005t^2 + 0.024t^3 − 0.0045t^4

undefined

6 0
2 years ago
Solve the equation for x by graphing.-4x-1 5x=4
Gemiola [76]

Answer: Undefined

Step-by-step explanation:

slope is undefined

no y intercept

This line is vertical

4 0
4 years ago
What is the domain of f(x) = 3x - 27
Olin [163]

9514 1404 393

Answer:

  {x | x is a real number}

Step-by-step explanation:

The domain of any polynomial function is "all real numbers."

6 0
3 years ago
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