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JulsSmile [24]
2 years ago
11

Dani wants to spend less than $25 on a birthday present for her friend. If she buys a necklace for $9.50, how many pairs of earr

ings, e, can she buy for $3.75 each without exceeding her budget? Enter your answer in the box.
Mathematics
1 answer:
aleksklad [387]2 years ago
5 0

Answer:

4

Step-by-step explanation:

Since it costs $3.75 for every earring, multiply e by 3.75 like this: 3.75e

Add 9.5 on top of that since Dani already bought the necklace for $9.50

3.75e + 9.5

This sum has to be less than or equal to 25 because the budget is $25

3.75e + 9.5 ≤ 25

To find e subtract 9.5 from both sides

3.75e + 9.5 ≤ 25

          - 9.5    - 9.5

3.75e ≤ 15.5

Divide both sides by 3.75

3.75e/3.75 = 15.5/3.75 = 4.133...

You can't buy 0.133 of an earring, so the max amount of earrings she can buy is 4.

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Work out the circumference of this circle.
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Answer: 52.7856cm

Step-by-step explanation:

Circumference of a circle = 2πr

Note that radius = Diameter / 2 = 16.8/2 = 8.4cm

Circumference = 2πr

= 2 × 3.142 × 8.4

= 52.7856cm

Therefore, the circumference of the circle is 52.7856cm

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3 years ago
From a group of 12 students, we want to select a random sample of 4 students to serve on a university committee. How many combin
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Answer:

495 combinations of 4 students can be selected.

Step-by-step explanation:

The order of the students in the sample is not important. So we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

How many combination of random samples of 4 students can be selected?

4 from a set of 12. So

C_{n,x} = \frac{12!}{4!(8)!} = 495

495 combinations of 4 students can be selected.

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Llana [10]

Answer:

The line slopes upwards from left to right wit a positive gradient and cuts the y-axis at y=2 and the x-axis at x=-3/2

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We first rearrange the equation to the order y=mx+c where m is the gradient and c the y intercept.

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The gradient is therefore 4/3 and the y intercept is 2.

At the c intercept, y=0

0=(4/3)x +2

(4/3)x=-2

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The line slopes upwards from left to right with a positive gradient and cuts the y-axis at y=2 and the x-axis at x=-3/2

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