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JulsSmile [24]
2 years ago
11

Dani wants to spend less than $25 on a birthday present for her friend. If she buys a necklace for $9.50, how many pairs of earr

ings, e, can she buy for $3.75 each without exceeding her budget? Enter your answer in the box.
Mathematics
1 answer:
aleksklad [387]2 years ago
5 0

Answer:

4

Step-by-step explanation:

Since it costs $3.75 for every earring, multiply e by 3.75 like this: 3.75e

Add 9.5 on top of that since Dani already bought the necklace for $9.50

3.75e + 9.5

This sum has to be less than or equal to 25 because the budget is $25

3.75e + 9.5 ≤ 25

To find e subtract 9.5 from both sides

3.75e + 9.5 ≤ 25

          - 9.5    - 9.5

3.75e ≤ 15.5

Divide both sides by 3.75

3.75e/3.75 = 15.5/3.75 = 4.133...

You can't buy 0.133 of an earring, so the max amount of earrings she can buy is 4.

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4 = 3/4m - 6 pls help me ASAP and check the answer
laila [671]

Answer:

m = 3/40

Step-by-step explanation:

4 = 3/4m - 6

m*4 = m(3/4m -6)

4m = m*3/4m + m*-6

4m = 3/4 - 6m

6m + 4m = 3/4

10m = 3/4

m = (3/4)/10

m = 3/40

check:

4 = 3/(4*3/40) - 6

4 = 3/(12/40) - 6

4 = (3*40)/12 - 6

4 = 120/12 - 6

4 = 10 - 6

4 0
3 years ago
The width of a rectangle is 12 units. Can the perimeter x of the rectangle can be 60 units when its length y is 18 units? (1 poi
juin [17]

If the width is 12 and the length is 18, the perimeter of the rectangle is 12 + 12 + 18 + 18, or 60. So yes the perimeter can be 60.

8 0
3 years ago
2x+3y=1 and y=-2 - 9 solve using linear combination method. Please explain steps.
kaheart [24]

Answer:

x=17

Step-by-step explanation:

2x+3y=1

y=-2-9

  • In order to combine these two equations, an idea you need to keep in mind is finding a way of setting these equations as equal to each other. I saw that each equation shared a common value, y. In this case, we need to isolate y in the first equation so that both equations =y.

2x+3y=1

3y=-2x+1

\frac{3y}{3}=\frac{-2x+1}{3}

y=-\frac{2}{3}x+\frac{1}{3}

  • With this, we now know that both -2-9 and -\frac{2}{3}x+\frac{1}{3} are equal to y, so we can set them equal to each other.

y=-\frac{2}{3}x+\frac{1}{3}

y=-11

-\frac{2}{3}x+\frac{1}{3}=-11

  • Reply to this if anything I'm saying or doing is confusing in any way, or if you find a mistake. :) Solve for x.

-\frac{2}{3}x+\frac{1}{3}=-11

-\frac{2}{3}x=-11-\frac{1}{3}

-\frac{2}{3}x =-\frac{33}{3}-\frac{1}{3}

-\frac{2}{3}x =-\frac{34}{3}

-\frac{2}{3}x(-\frac{3}{2})=-\frac{34}{3}(-\frac{3}{2})

x=\frac{102}{6}=17

x=17

  • Hopefully this answer is correct AND makes sense in terms of how I achieved it. Again, reply to this with any questions or mistakes I made and I'll do my best to answer or fix them.

 

4 0
3 years ago
What 1x0 -p1s yyyyrr
11111nata11111 [884]
0.

anything multiplied by 0 = 0.
4 0
2 years ago
A jewlery supply shop buys silver chains from a manufacturer for c dollars each, and then sells the chains at a 57% markup
kirza4 [7]

11. 57% = 0.57

12.  retail price = c + (0.57c)

13.  retail price = 45 + (0.57 x 45)

retail price = 45 + 25.65

retail price = $70.65

14. 57% was added to the original price of the chain which is $25.65

4 0
3 years ago
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