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3 years ago

4 consecutive odd integers add up to -200. Find the integers.

1 answer:

4 0

Let
x = first odd integer
x + 2 = second odd integer
x + 4 = third odd integer
x + 6 = fourth odd integer

x + (x + 2) + (x + 4) + (x + 6) = -200
4x = -200 - 2 - 4 - 6
4x = -212
x = -53

Therefore, the four consecutive integers are -53, -51, -49, -47.

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Arte-miy333 [17]

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if you have a bad credit score it can increase your debt ratio

Step-by-step explanation:

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3 years ago

Roy uses 1/4 cup of batter for each muffin. make a list of batter he will use depending on the number of muffins he makes.

evablogger [386]

1 muffin = 1/4 cup
2 muffins = 1/2 cup
3 muffins = 3/4 cup
4 muffins = 1 cup
5 muffins = 1 and 1/4 cup
6 muffins = 1 and 1/2 cup

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3 years ago

Read 2 more answers

Simplify square root of 2 over cube root of 2.

Fed [463]

Answer:

2 to the power of one sixth

Step-by-step explanation:

Assuming you don't already know this, any type of root can be expressed as an exponent. Generally speaking:

$\sqrt[n]{x} = {x}^{ \frac{1}{n} }$

So you can rewrite the given fraction as

$\frac{ {2}^{ \frac{1}{2} } }{ {2}^{ \frac{1}{3} } }$

and then reduce as you normally would. That is, if the bases of the numerator and denominator are the same, then you can subtract the denominator's exponent from the numerator's exponent like so:

$\frac{ {2}^{ \frac{1}{2} } }{ {2}^{ \frac{1}{3} } } = {2}^{ \frac{1}{2} - \frac{1}{3} }$

Since

$\frac{1}{2} - \frac{1}{3} = \frac{3}{6} - \frac{2}{6} = \frac{1}{6}$

the answer is

${2}^{ \frac{1}{6} } \: or \: \sqrt[6]{2}$

3 0

3 years ago

Read 2 more answers

Michael is paid $9 per hour to work at the movie theater and $7 per hour when he helps his aunt at her bakery. Michael cannot wo

KIM [24]

Answer:

The first one/$9 an hour job.

Step-by-step explanation:

For every 32 hours he works at the $9 per hour job he makes $288.

On the other hand, for every 32 hours he works at the $7 per hour job he only makes $224.

So the only one that'll work where he gets at least $251 is the $9 an hour job.

<u>Hope this helps and have a nice day!</u>

6 0

3 years ago

Write the algebraic expression for the difference between the squares of two numbers.

V125BC [204]

The algebraic expression for the difference between the squares of the two numbers, supposing the two numbers to be a and b, is

a² - b² = (a + b)(a - b).

An algebraic expression is a combination of terms, where the terms are separated using mathematical operators like plus (+), minus (-), multiply (*), and divide (/).

The terms are combinations of numerals and variables.

Variables are represented alphanumerically, which can hold any value as per the expression they are used in.

In the question, we are asked to write the algebraic expression for the difference between the squares of two numbers.

We assume the two numbers to be a and b respectively.

Thus, we are asked to write an expression for the difference between the square of a and square of b, that is, we are asked to write an expression for a² - b².

We know that a² - b² is an identity, which can be shown as (a + b)(a - b).

Thus, the algebraic expression for the difference between the squares of the two numbers, supposing the two numbers to be a and b, is a² - b² = (a + b)(a - b).

Learn more about algebraic expressions at

brainly.com/question/2241589

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2 years ago