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beks73 [17]
3 years ago
15

4 consecutive odd integers add up to -200. Find the integers.

Mathematics
1 answer:
Alexeev081 [22]3 years ago
4 0
Let
x = first odd integer
x + 2 = second odd integer
x + 4 = third odd integer
x + 6 = fourth odd integer

x + (x + 2) + (x + 4) + (x + 6) = -200
4x = -200 - 2 - 4 - 6
4x = -212
x = -53

Therefore, the four consecutive integers are -53, -51, -49, -47.
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Answer:

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Step-by-step explanation:

A sequence of numbers is said to be in arithmetic progression of each term of the sequence has same common difference.

Now, here first term a1 = 1/4

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Now, Common difference (d) = a2 - a1 = a3 - a2

Now, a2 - a1 = \frac{5}{16}  - \frac{1}{4}  = \frac{5 - 4}{16}  = \frac{1}{16}

Now, a3 - a2 =  \frac{3}{8}  - \frac{5}{16}  = \frac{6 - 5}{16}  = \frac{1}{16}

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