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miv72 [106K]
3 years ago
13

Write the expressions without using log. Can someone please help with this?

Mathematics
1 answer:
goldenfox [79]3 years ago
6 0
\bf \textit{logarithm of factors}\\\\
log_{{  a}}(xy)\implies log_{{  a}}(x)+log_{{  a}}(y)
\\\\\\
\textit{Logarithm of rationals}\\\\
log_{{  a}}\left(  \frac{x}{y}\right)\implies log_{{  a}}(x)-log_{{  a}}(y)
\\\\\\
\textit{Logarithm of exponentials}\\\\
log_{{  a}}\left( x^{{  b}} \right)\implies {{  b}}\cdot  log_{{  a}}(x)\\\\
-------------------------------

\bf log(m^3n)\implies log(m^3)+log(n)\implies 3log(m)+log(n)
\\\\\\
\boxed{3k+v}
\\\\\\
log\left(\cfrac{m}{n^3}  \right)\implies log(m)-log(n^3)\implies log(m)-3log(n)
\\\\\\
\boxed{k-3v}
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What is the sum of 1.57 and 6.88?

Ok, so lets work this out together!

Sum means add.

   6.88
+ 1.57

That would be: 

= 8.45

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hichkok12 [17]
Joint variation means that w=kxy where k is constant.
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What are the next two numbers in the sequence: 0.5, 1.0, 2.0, 4.0..... *
Ivanshal [37]

Answer:

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times the before number by itself

8 0
3 years ago
35 POINTS AVAILABLE
aliina [53]

Answer:

Part 1) The length of each side of square AQUA is 3.54\ cm

Part 2) The area of the shaded region is (486\pi-648)\ units^{2}

Step-by-step explanation:

Part 1)

<em>step 1</em>

Find the radius of the circle S

The area of the circle is equal to

A=\pi r^{2}

we have

A=25\pi\ cm^{2}

substitute in the formula and solve for r

25\pi=\pi r^{2}

simplify

25=r^{2}

r=5\ cm

<em>step 2</em>

Find the length of each side of square SQUA

In the square SQUA

we have that

SQ=QU=UA=AS

SU=r=5\ cm

Let

x------> the length side of the square

Applying the Pythagoras Theorem

5^{2}=x^{2} +x^{2}

5^{2}=2x^{2}

x^{2}=\frac{25}{2}\\ \\x=\sqrt{\frac{25}{2}}\ cm\\ \\ x=3.54\ cm

Part 2) we know that

The area of the shaded region is equal to the area of the larger circle minus the area of the square plus the area of the smaller circle

<em>Find the area of the larger circle</em>

The area of the circle is equal to

A=\pi r^{2}    

we have

r=AB=18\ units

substitute in the formula

A=\pi (18)^{2}=324\pi\ units^{2}

step 2

Find the length of each side of square BCDE

we have that

AB=18\ units

The diagonal DB is equal to

DB=(2)18=36\ units

Let

x------> the length side of the square BCDE

Applying the Pythagoras Theorem

36^{2}=x^{2} +x^{2}

1,296=2x^{2}

648=x^{2}

x=\sqrt{648}\ units

step 3

Find the area of the square BCDE

The area of the square is

A=(\sqrt{648})^{2}=648\ units^{2}

step 4

Find the area of the smaller circle

The area of the circle is equal to

A=\pi r^{2}    

we have

r=(\sqrt{648})/2\ units

substitute in the formula

A=\pi ((\sqrt{648})/2)^{2}=162\pi\ units^{2}  

step 5

Find the area of the shaded region

324\pi\ units^{2}-648\ units^{2}+162\pi\ units^{2}=(486\pi-648)\ units^{2}

7 0
3 years ago
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