The answer is 24 square units
Answer:
74.22% probability that a family of four will spend more than $400.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability that a family of four will spend more than $400?
This is 1 subtracted by the pvalue of Z when X = 400. So



has a pvalue of 0.2578.
So there is a 1-0.2578 = 0.7422 = 74.22% probability that a family of four will spend more than $400.
Answer:
30
Step-by-step explanation:
40- 10 equals 30
the range is the maximum divided by the minimum.
Answer:
No, does not differ.
Step-by-step explanation:
Given that there are two intersections route 7 and route 62.
At the intersection of Route 7 and North Shrewsbury in Clarendon, Vermont, 154 vehicles were observed to encounter a yellow light in the indecision zone, and 21 of them ran the red light. At the intersection of Route 62 and Paine Turnpike in Berlin, Vermont, 183 vehicles entered the intersection in the indecision zone, and 20 ran the red light.
Let p1 be the first proportion and p2 the second
We want to test whether these two proportions differ

(two tailed test at 5% significance level)
test statistic = 

Z statistic = 
p value = 0.4473
Since p >0.05 accept null hypothesis.
There is no significant difference and the proportion of redlight runners does not differ between the two intersections