y=2(3)x+1
−
y=2(3)x
y-y=2(3)x+1−2(3)x
the answer would be 0=1
but if it is asking u if it is false or true it is
0=1 is false, therefore the system of equations has no solutions
Answer:
- 16√3
- -45+15i
- √255
- 6√2 +3√10
Step-by-step explanation:
1)

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2)

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3)

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4)

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The applicable identities are ...

Answer: 7
Add up the values to get 4+10 = 14
Then divide that result over 2 to get 14/2 = 7
This is using the midpoint formula.
Answer:
so on the graph you can
Step-by-step explanation:
first the y axis number comes first so you look at that the you do the x axis it should look like 2,3 or 2,-3 hope this works