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3 years ago

HELP!! Jackie cut a piece of paper along its diagonal, as shown below, forming two triangles.

Mathematics

2 answers:

mart [117]3 years ago

8 0

Answer:

Step-by-step explanation:

8_murik_8 [283]3 years ago

3 0

Answer: The two dimensions are the same in the triangles as they were in the rectangle.

Step-by-step explanation:

Height of a triangle is the perpendicular distance from the one vertex of the triangle to the one side of the triangle( that side is called base of the triangle).

Let the length of the given rectangle is l unit and width of the rectangle is b unit,

When the rectangle is cut along its diagonal,

Then we found two right triangles,

In which both having dimensions,

height = b and base = l,

Thus, the dimension of the triangles are same as the rectangles.

⇒ First option is correct.

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How do you write the equation of a line and stop intercept form from that passes through the point -3, 5

mr_godi [17]

Y=2/3x -5/2

Slope is equal to the parallel line (2/3)
Find y intercept by setting y and x equal the given coordinates and solve.

8 0

3 years ago

For every boy in an advanced math course there are 3 girls who are taking the course.

Nutka1998 [239]

Answer:

If 32 students are enrolled in the course, there would be 24 girls.

Step-by-step explanation:

Given that For every boy in an advanced math course there are 3 girls who are taking the course.

It means if there are four students in the class. There would be 3 girls and 1 boy. Thus, 75% of the students are girls.

Given that there are 32 students enrolled in the course.

75% of 32 = 75/100 × 32

= 24

Thus, if 32 students are enrolled in the course, there would be 24 girls.

7 0

3 years ago

The graph of which function has a minimum located at (4, –3)?

valentinak56 [21]

Answer:

None of the options is the answer to the question

Step-by-step explanation:

we know that

The equation of a vertical parabola into vertex form is equal to

$f(x)=a(x-h)^{2}+k$

where

(h,k) is the vertex of the parabola

case A) we have

$f(x)=x^{2}+4x-11$

In this case the x-coordinate of the vertex will be negative

therefore

case A is not the solution

case B) we have

$f(x)=-2x^{2}+16x-35$

This case is a vertical parabola open downward (the vertex is a maximum)

The vertex is the point $(4,-3)$ <u>but is not a minimum</u>

see the attached figure

therefore

case B is not the solution

case C) we have

$f(x)=x^{2}-4x+5$

Convert into vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)-5=x^{2}-4x$

Complete the square. Remember to balance the equation by adding the same constants to each side

$f(x)-5+4=(x^{2}-4x+4)$

$f(x)-1=(x^{2}-4x+4)$

Rewrite as perfect squares

$f(x)-1=(x-2)^{2}$

$f(x)=(x-2)^{2}+1$ --------> vertex form

The vertex is the point $(2,1)$

therefore

case C is not the solution

case D) we have

$f(x)=2x^{2}-16x+35$

Convert into vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)-35=2x^{2}-16x$

Factor the leading coefficient

$f(x)-35=2(x^{2}-8x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$f(x)-35+32=2(x^{2}-8x+16)$

$f(x)-3=2(x^{2}-8x+16)$

Rewrite as perfect squares

$f(x)-3=2(x-4)^{2}$

$f(x)=2(x-4)^{2}+3$ --------> vertex form

The vertex is the point $(4,3)$

therefore

case D is not the solution

The answer to the question will be the function

$f(x)=2x^{2}-16x+29$

7 0

4 years ago

Read 2 more answers

An architect is drawing up plans for a house. The rectangular living room is 4 feet longer than it is wide. The

I am Lyosha [343]

Answer b

Step-by-step explanation:

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3 years ago

Draw a set of collinear points R,S and T

Nadusha1986 [10]

When they are collinear, they lie on the same straight line

6 0

4 years ago