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iren2701 [21]
3 years ago
13

3x+6/x^2-x-6+2x/x^2+x-12

Mathematics
1 answer:
Tanzania [10]3 years ago
6 0
\dfrac{3x+6}{x^2-x-6} +  \dfrac{2x}{x^2+x-12}

= \dfrac{3(x+2)}{(x + 2)(x - 3)} +  \dfrac{2x}{ (x - 3)(x + 4)}

= \dfrac{3}{(x - 3)} +  \dfrac{2x}{ (x -3)(x + 4)}

= \dfrac{3(x+4)}{(x - 3)(x + 4)} +  \dfrac{2x}{ (x -3 )(x + 4)}

= \dfrac{3(x+4) + 2x }{(x - 3)(x + 4)}

= \dfrac{3x+12 + 2x }{(x - 3)(x + 4)}

= \dfrac{5x+12}{(x - 3)(x + 4)}



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Hey all, can I get the answer + explanation for this? Would be much appreciated.
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Answer:

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Step-by-step explanation:

Let's draw an imaginary dot in the middle of that <u>line</u> which runs between those two parallel lines, and now lets look at it as an angle.

This lines' angle is 180 degrees. Now lets move those two parallel lines together on the imaginary dot in the middle.

We can see that on the left side is one degree and the other side is another, however when we put them together we get the angle measurement of the our line which we identified was 180.

Now that we can see that our two angles must equal 180 when put together we know and can say that:

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So, lets work this out like basic algebra now.

40 + x + 20 = 180

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Hope this helps :)

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