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iren2701 [21]
3 years ago
13

3x+6/x^2-x-6+2x/x^2+x-12

Mathematics
1 answer:
Tanzania [10]3 years ago
6 0
\dfrac{3x+6}{x^2-x-6} +  \dfrac{2x}{x^2+x-12}

= \dfrac{3(x+2)}{(x + 2)(x - 3)} +  \dfrac{2x}{ (x - 3)(x + 4)}

= \dfrac{3}{(x - 3)} +  \dfrac{2x}{ (x -3)(x + 4)}

= \dfrac{3(x+4)}{(x - 3)(x + 4)} +  \dfrac{2x}{ (x -3 )(x + 4)}

= \dfrac{3(x+4) + 2x }{(x - 3)(x + 4)}

= \dfrac{3x+12 + 2x }{(x - 3)(x + 4)}

= \dfrac{5x+12}{(x - 3)(x + 4)}



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Answer with explanation:

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\frac{dy}{dx}

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Part 2)

The product of the 2 functions is shown below

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Diffrentiating both sides with respect to 'x' we get

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8 0
3 years ago
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nikitadnepr [17]
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