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2 years ago

Which relation is a function?

Mathematics

1 answer:

Ksivusya [100]2 years ago

8 0

B. To see if it’s a function, it has to pass the vertical line test. That means draw a vertical line (going up and down) through any point on the graph and it can only go through one point. If it goes through more than 1, it’s not a function. Like in graph A, if you draw a vertical line at x=-2, it will go through two points, same at x=2. For graph b, no matter where you move a vertical line, it only passes through one point at a time, so it passes the vertical line test.

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Wirte an expression that should have a variable and a constant

e-lub [12.9K]

7x+5
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2 years ago

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Use the following graph of the function f(x) = 2x3 + x2 − 3x + 1 to answer this question: graph of 2x cubed plus x squared minus

Zina [86]

Answer:

Step-by-step explanation:

f(x) = 2x^3 + x^2 − 3x + 1

f'(x) = 6x^2 + 2x − 3

The slope at -2:

f'(-2) = 6(-2)^2 + 2(-2) − 3

f'(-2) = 24 + -4 − 3

f'(-2) = 17

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The slope at 0:

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2 years ago

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Hi. Please I need help with these questions.

ElenaW [278]

Answer:

Q 12 roots of the equation

$2x^{2} -6+1=0 \\= (x-\frac{\sqrt{10} }{2})(x+\frac{\sqrt{10} }{2})\\$

∝ = $\frac{\sqrt{10} }{2}$

β = $-\frac{\sqrt{10} }{2}$

no matter if u oppose the root

(i) 2( $\frac{\sqrt{10} }{2}$ ) $(-\frac{\sqrt{10} }{2} )^{2}$ +2 $(\frac{\sqrt{10} }{2} )^{2}$ ( $-\frac{\sqrt{10} }{2}$ )+2(

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the equation is

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3 years ago

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2 years ago

A car rental company has two rental rates. rate 1 is $64 per day pluus $.16 per mile. rate 2 is $128 per day plus $.08 per mile.

kvv77 [185]

D is days
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3 years ago