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nignag [31]
3 years ago
13

What is the half-life of 239Pu (the radioactive waste from nuclear power plants)? Remember, the half-life is how long it takes f

or half of the radioactive materials to decay.
Chemistry
1 answer:
vovikov84 [41]3 years ago
8 0

Answer:

The half-life of Plutonium 239 (Pu 239) is 24,100 years.

Explanation:

Half-life is the time required for a quantity to reduce to half of its initial value. This means that in 241000 years, 100g of Pu 239 would be reduced to 50g.

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What is the maximum rate constant for the recombination of iodine atoms under these conditions?
Mars2501 [29]
65 ( \frac{-}{+} 6) x  10^{9}  liter^{2} mole^{-2}sec^{-1}
5 0
3 years ago
How many significant digits are in 2804
docker41 [41]

Answer:

4 significant digits

Explanation:

Zeroes placed between other digits are always significant

4 0
3 years ago
Please answer!! If you're not 100% sure on an answer, you can tell me.
VladimirAG [237]

The one after metamorphic rock is melting.

5 0
3 years ago
A. If both Assertion & Reason are true and the reason is the correct explanation of the assertion. B. If both Assertion &amp
Fofino [41]

Answer:

D- Assertion is false and Reason is true

Explanation:

Precipitation is said to have occurred when an insoluble product is formed from soluble ones. Let us take an instance;

BaCl2(aq) + H2SO4(aq) -------> BaSO4(s) + 2HCl(aq)

The barium sulphate so formed is an insoluble product obtained from the reaction of soluble barium chloride and sulphuric acid. This is a typical example of a double replacement reaction as the both ions exchanged partners.

Thus, the assertion is false but the reason is true.

8 0
3 years ago
A 850.0 mL cylinder containing B2H6 at a pressure of 0.900 atm is connected by a valve to 1000 mL cylinder containing C6H6 at 60
8_murik_8 [283]

Answer:

The partial pressure of C_6H_6 when the valve is opened is 328.6 Torr.

Explanation:

Initial pressure of the C_6H_6=P_1=608.0 Torr

Initial volume of the C_6H_6=V_1=1000 mL

After opening the valve :

Final pressure or partail pressure of the C_6H_6=P_2

Final volume of the C_6H_6=V_2=1000 mL+850.0 mL=1850.0 mL

P_1V_1=P_2V_2 ( Boyle's law)

P_2=\frac{608.0 Torr \times 1000 mL}{1850.0 mL}=328.6 Torr

The partial pressure of C_6H_6 when the valve is opened is 328.6 Torr.

4 0
3 years ago
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