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kari74 [83]
3 years ago
9

Which organism is able to cause an infection

Chemistry
2 answers:
spin [16.1K]3 years ago
8 0

Answer: The answer is bacteria. The correct answer is The letter B or the seconed one!

Temka [501]3 years ago
5 0

Answer:

bacteria

Explanation:

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PLS HELP ASAP I WILL GOVE BRAINLYEST
Radda [10]

Answer:

4 genetically different daughter cells

Explanation:

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5 0
2 years ago
With white light, a team measured a 0.7% percent change with 3.5g of plant matter in a one liter container. Convert
Strike441 [17]

moles CO₂ = 5.57.10⁻⁴

<h3>Further explanation   </h3>

A mole is a number of particles(atoms, molecules, ions)  in a substance

Can be formulated :

\tt mol=\dfrac{mass}{MW}

0.7% percent change with 3.5g of plant matter

mass :

\tt 0.7\%\times 3.5~g=0.0245~g

moles :

\tt moles=\dfrac{0.0245}{44}=0.000557=5.57.10^{-4}

5 0
3 years ago
The highest concentration of dissolved gases is found in what type of water mass?
Maurinko [17]
Elephants are really cool
7 0
2 years ago
In a synthesis reaction you start with 1.7L of Hydrogen how many liters of water will be produced?
jolli1 [7]

15.3 litres of water will be produced if we take 1.7 litres of Hydrogen

Explanation:

Let's take a look over synthesis reaction;

H_{2}+ O_{2}<u>                         </u>H_{2}O<u />

<u>Balancing the chemical reaction;</u>

2H_{2} +O_{2}<u>                        </u>2H_{2}O<u />

Thus, 2 moles of hydrogen molecules are required to form 2 moles of water molecules.

<u>Equating the molarity;</u>

<u />\frac{1.7*1}{2*2} = \frac{x*1}{2*18}

           (Since, the molecular mass of hyd and water is 2 and 18 respectively)

x=\frac{1.7*2*18}{2*2}

x= 15.3 litres.

Thus,15.3 L of water will be produced if we take 1.7 litres of Hydrogen in a synthesis reaction.

6 0
3 years ago
4. How many grams of ammonium carbonate are needed to decompose in order to produce
Thepotemich [5.8K]

Answer:

14.23g of (NH4)2CO3

Explanation:

We'll begin by writing the balanced equation for the reaction.

(NH4)2CO3 –> (NH4)2O + CO2

Next,, we shall determine the mass of (NH4)2CO3 that decomposed and the mass of CO2 produced from the balanced equation. This is illustrated below:

Molar mass of (NH4)2CO3 = 2[14+(4x1)] + 12 + (16x3)

= 2[14 +4] + 12 + 48

= 2[18] + 60 = 96g/mol

Mass of (NH4)2CO3 from the balanced equation = 1 x 96 = 96g

Molar mass of CO2 = 12 + (2x16) = 44g/mol

Mass of CO2 from the balanced equation = 1 x 44 = 44g.

Summary:

From the balanced equation above,

96g of (NH4)2CO3 decomposed to produce 44g of CO2.

Finally, we can determine the mass of (NH4)2CO3 that decomposed to produce 6.52g of CO2 as follow:

From the balanced equation above,

96g of (NH4)2CO3 decomposed to produce 44g of CO2.

Therefore, Xg of (NH4)2CO3 will decompose to produce 6.52g of CO2 i.e

Xg of (NH4)2CO3 = (96 x 6.52)/44

Xg of (NH4)2CO3 = 14.23g

Therefore, 14.23g of (NH4)2CO3 is needed to produce 6.52g of CO2.

4 0
3 years ago
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