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Ne4ueva [31]
4 years ago
12

Steph says that the numbers 38 and 40 are relatively

Mathematics
1 answer:
nikdorinn [45]4 years ago
7 0

Answer:

That's true because they can be different numbers but they are both even.

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Need help on geometry #3
Tresset [83]

Answer:

see explanation

Step-by-step explanation:

∠ PQS + ∠SQR = ∠ PQR , substitute values

13x + 4 + 10x - 1 = 141 , that is

23x + 3 = 141 (subtract 3 from both sides )

23x = 138 ( divide both sides by 23 )

x = 6

Thus

∠ PQS = 13x + 4 = 13(6) + 4 = 78 + 4 = 82°

∠ SQR = 10x - 1 = 10(6) - 1 = 60 - 1 = 59°

3 0
3 years ago
Zoom In! Help needed immediately
lara31 [8.8K]
<h3>QUESTION A:</h3>

Graph B.

The information is presented most clearly here, being centered and climbing steadily which prevents the influence of bias in the presentation. As stated, his presentation is intended to be neutral.

<h3>QUESTION B:</h3>

Graph C.

This graph tricks the human brain into thinking that the increase is less prominent than we might perceive it in Graph A or B. This is because it is located lower and has a shallower slope. The campaign that wants to prevent immediate radical action (action which would harm the native species) would want to use this one as it might convince the city counsel that the issue is not urgent enough to take such actions so quickly.

3 0
2 years ago
There is a loss of Rs 5 when a watch is sold at the discount of 10%. IF the watch is sold at the discount of 5%, there is profit
Colt1911 [192]
At disc of 10% there was 5rupees loss and at disc of 5 % dis there was 22.5 profit
so 5% *x= 22.5+5=27.5
x=27.5 *20
x=550
8 0
3 years ago
PLEASE HELP!!!!!
Katena32 [7]

Answer:6018

Step-by-step explanation:

Given Sequence

-282-266-250-234.....

It represent an A.P. with

first term a=-282

common difference d=16

So sum of 51 term

S_n=\frac{n}{2}[2a+(n-1)d]

S_{51}=\frac{51}{2}\times [2\times (-282)+(51-1)16]

S_{51}=\frac{51}{2}\times [-564+800]

S_{51}=\frac{51}{2}\times [236]

S_{51}=51\times 118

S_{51}=6018

7 0
3 years ago
Esmeralda received a bag of jellybeans that contained a mixture of regular flavored jellybeans and "surprise" jellybeans. The ba
WARRIOR [948]

Answer:

6 jellybean

Step-by-step explanation:

Given that:

Esmeralda received a bag of jellybean the contains regular flavored jelly beans and surprise jelly bean.

Consider the regular flavored jellybean to be = r;  &

The surprise jelly bean.= s

From the bag, there are 40 jellybeans of which 15% is surprise jellybean.

Therefore the number of expected surprise jellybeans is:

= total number of jellybeans × percentage of surprise jellybean

= 40 × (15 /100)

= 6 jellybean

If  6 surprise jellybean is presented in the bag; then the number of regular flavored jellybean = 40 - 6 = 34 regular flavored jellybean

3 0
3 years ago
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