Answer:
see explanation
Step-by-step explanation:
∠ PQS + ∠SQR = ∠ PQR , substitute values
13x + 4 + 10x - 1 = 141 , that is
23x + 3 = 141 (subtract 3 from both sides )
23x = 138 ( divide both sides by 23 )
x = 6
Thus
∠ PQS = 13x + 4 = 13(6) + 4 = 78 + 4 = 82°
∠ SQR = 10x - 1 = 10(6) - 1 = 60 - 1 = 59°
<h3>
QUESTION A:</h3>
Graph B.
The information is presented most clearly here, being centered and climbing steadily which prevents the influence of bias in the presentation. As stated, his presentation is intended to be neutral.
<h3>
QUESTION B:</h3>
Graph C.
This graph tricks the human brain into thinking that the increase is less prominent than we might perceive it in Graph A or B. This is because it is located lower and has a shallower slope. The campaign that wants to prevent immediate radical action (action which would harm the native species) would want to use this one as it might convince the city counsel that the issue is not urgent enough to take such actions so quickly.
At disc of 10% there was 5rupees loss and at disc of 5 % dis there was 22.5 profit
so 5% *x= 22.5+5=27.5
x=27.5 *20
x=550
Answer:6018
Step-by-step explanation:
Given Sequence

It represent an A.P. with
first term 
common difference 
So sum of 51 term
![S_n=\frac{n}{2}[2a+(n-1)d]](https://tex.z-dn.net/?f=S_n%3D%5Cfrac%7Bn%7D%7B2%7D%5B2a%2B%28n-1%29d%5D)
![S_{51}=\frac{51}{2}\times [2\times (-282)+(51-1)16]](https://tex.z-dn.net/?f=S_%7B51%7D%3D%5Cfrac%7B51%7D%7B2%7D%5Ctimes%20%5B2%5Ctimes%20%28-282%29%2B%2851-1%2916%5D)
![S_{51}=\frac{51}{2}\times [-564+800]](https://tex.z-dn.net/?f=S_%7B51%7D%3D%5Cfrac%7B51%7D%7B2%7D%5Ctimes%20%5B-564%2B800%5D)
![S_{51}=\frac{51}{2}\times [236]](https://tex.z-dn.net/?f=S_%7B51%7D%3D%5Cfrac%7B51%7D%7B2%7D%5Ctimes%20%5B236%5D)


Answer:
6 jellybean
Step-by-step explanation:
Given that:
Esmeralda received a bag of jellybean the contains regular flavored jelly beans and surprise jelly bean.
Consider the regular flavored jellybean to be = r; &
The surprise jelly bean.= s
From the bag, there are 40 jellybeans of which 15% is surprise jellybean.
Therefore the number of expected surprise jellybeans is:
= total number of jellybeans × percentage of surprise jellybean
= 40 × (15 /100)
= 6 jellybean
If 6 surprise jellybean is presented in the bag; then the number of regular flavored jellybean = 40 - 6 = 34 regular flavored jellybean