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3 years ago

What is the relationship with 0.04 and 0.004

1 answer:

6 0

Well,

You could say that 0.04 is greater than 0.004.
0.04 > 0.004

You could be more specific and say how much greater 0.04 is compared to 0.004.
0.04 = 10(0.004)

You can also make general conclusions about the two numbers.

"0.04 and 0.004 both are less than 1."

"Both numbers have fractional forms that can be simplified."

"Both numbers have a zero to the left of the decimal point."

And so on and on.

You might be interested in

Match each value with its formula for ABC.

MariettaO [177]

The solution to the question is:

c is 6 = $\sqrt{a^{2} + b^{2} -2abcosC }$

b is 5 = $\sqrt{a^{2} + c^{2} -2accosB }$

cosB is 2 = $\frac{a^{2} + c^{2} - b^{2} }{2ac}$

a is 4 = $\sqrt{b^{2} + c^{2} -2bccosA }$

cosA is 3 = $\frac{b^{2} + c^{2} -a^{2} }{2bc}$

cosC is 1 = $\frac{b^{2} + a^{2} - c^{2} }{2ab}$

<h3>What is cosine rule?</h3>

it is used to relate the three sides of a triangle with the angle facing one of its sides.

The square of the side facing the included angle is equal to the some of the squares of the other sides and the product of twice the other two sides and the cosine of the included angle.

Analysis:

If c is the side facing the included angle C, then

$c^{2}$ = $a^{2}$ + $b^{2}$ -2ab cos C-----------------1

then c = $\sqrt{a^{2} + b^{2} -2abcosC }$

if b is the side facing the included angle B, then

$b^{2}$ = $a^{2}$ + $c^{2}$ -2accosB-----------------2

b = $\sqrt{a^{2} + c^{2} -2accosB }$

from equation 2, make cosB the subject of equation

2ac cosB = $a^{2}$ + $c^{2}$ - $b^{2}$

cosB = $\frac{a^{2} + c^{2} - b^{2} }{2ac}$

if a is the side facing the included angle A, then

$a^{2}$ = $b^{2}$ + $c^{2}$ -2bccosA--------------------3

a = $\sqrt{b^{2} + c^{2} -2bccosA }$

from equation 3, making cosA subject of the equation

2bcosA = $b^{2}$ + $c^{2}$ - $a^{2}$

cosA = $\frac{b^{2} + c^{2} -a^{2} }{2bc}$

from equation 1, making cos C the subject

2abcosC = $b^{2}$ + $a^{2}$ - $c^{2}$

cos C = $\frac{b^{2} + a^{2} - c^{2} }{2ab}$

In conclusion,

c is 6 = $\sqrt{a^{2} + b^{2} -2abcosC }$

b is 5 = $\sqrt{a^{2} + c^{2} -2accosB }$

cosB is 2 = $\frac{a^{2} + c^{2} - b^{2} }{2ac}$

a is 4 = $\sqrt{b^{2} + c^{2} -2bccosA }$

cosA is 3 = $\frac{b^{2} + c^{2} -a^{2} }{2bc}$

cosC is 1 = $\frac{b^{2} + a^{2} - c^{2} }{2ab}$

Learn more about cosine rule: brainly.com/question/4372174

$SPJ1

4 0

2 years ago

Which choice shows a correct way to find 6 × 3 × 5?

bekas [8.4K]

There are no choices, but anything that has those option are right.

6 0

3 years ago

Read 2 more answers

Brianna went into a bakery and bought 2 cookies and 3 brownies, costing a total of $9.50. Nevaeh went into the same bakery and b

Lerok [7]

Answer:

Variable x = cost of cookies

Variable y = cost of brownies

System of equations:

2x + 3y = 9.50

10x + 6y = 20.50

Step-by-step explanation:

Variable x: $ cookies

Variable y: $ brownies

2x + 3y = 9.50

10x + 6y = 20.50

I'm not entirely sure how to explain this one, but my best advice is to just take it step by step when doing these problems. Multiple questions can feel overwhelming so just focus on one question at a time.

3 0

3 years ago

If the legs of a right triangle are given by x2 - y2 and 2xy, then which expression equals the hypotenuse? choose all that apply

11Alexandr11 [23.1K]

Hypothenus = sqrt ((x^2 - y^2)^2 + (2xy)^2) = sqrt(x^4 - 2x^2y^2 + y^4 + 4x^2y^2) = sqrt(x^4 + 2x^2y^2 + y^4) = sqrt(x^2 + y^2)^2 = x^2 + y^2

3 0

3 years ago

It is known that the graph of the function y= x goes through the point A(4, −.5). Find k and plot its graph.

matrenka [14]

I will need to see a picture. I feel like I’m missing information.

5 0

3 years ago