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Nookie1986 [14]
3 years ago
14

What is the relationship with 0.04 and 0.004

Mathematics
1 answer:
sattari [20]3 years ago
6 0
Well,

You could say that 0.04 is greater than 0.004.
0.04 > 0.004

You could be more specific and say how much greater 0.04 is compared to 0.004.
0.04 = 10(0.004)

You can also make general conclusions about the two numbers.

"0.04 and 0.004 both are less than 1."

"Both numbers have fractional forms that can be simplified."

"Both numbers have a zero to the left of the decimal point."

And so on and on.
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svetoff [14.1K]

Do the 11% off first.

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if you do -40$ first then you have $12 left and 11% off that is $10.68.

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A hummingbird eggs’ mass is approximately 0.374 milligram. What is the mass of 4 Hummingbird eggs?
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Read 2 more answers
The points plotted below satisfy a polynomial equation. What type of extreme value does the graph have in the part that is visib
bezimeni [28]
Hi!

The graph shows an A) Maximum

A Maximum value appears in a graph when all other values of the polynomial are smaller in value i.e. are under it in an X-Y plot. This is expressed mathematically as:

There is a maximum if for a given x*: f(x*) ≥ f(x) for all x. 

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3 0
3 years ago
PLEASE HELP! The table shows the number of championships won by the baseball and softball leagues of three youth baseball divisi
Irina18 [472]

Answer:

Question 1: P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16}}{ \frac{4}{16}} = \frac{1}{2}

Question 2:

A. P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}

B. P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}

C. P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}

Step-by-step explanation:

Conditional probability is defined by

P(A|B)= \frac{P(A and B)}{P(B)}

with P(A and B) beeing the probability of both events occurring simultaneously.

Question 1:

B: Baseball League Championships won, beeing

P ( B ) = \frac{ 6 }{16}

Y: Championships won by the 10 - 12 years old, beeing

P ( Y)= \frac{ 4 }{ 16 }

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16} }{ \frac{4}{16} }  = \frac{1}{2}

Question 2.A:

Y: Championships won by the 10 - 12 years old, beeing

P ( Y)= \frac{ 4 }{ 16 }

B: Baseball League Championships won, beeing

P ( B ) = \frac{ 6 }{16}

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}

Question 2.B:

Z: Championships won by the 13 - 15 years old, beeing

P ( Z)= \frac{ 1 }{ 16 }

B: Baseball League Championships won, beeing

P ( B ) = \frac{ 6 }{16}

then

P( Z and B)= \frac{ 1 }{ 16 }[/tex]

By definition,

P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}

Question 3.B

Y: Championships won by the 10 - 12 years old, beeing

P ( Y)= \frac{ 4 }{ 16 }

Z: Championships won by the 13 - 15 years old, beeing

P ( Z)= \frac{ 1 }{ 16 }

then

P (Y or Z) = P(Y) + P(Z) = \frac{6}{16}

B: Baseball League Championships won, beeing

P ( B ) = \frac{ 6 }{16}

so

P((YorZ) and B)= \frac{3}{16}

By definition,

P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}

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3 years ago
A New dog leash with an attached flashlight was on dale for 20% off. if the original price was $16.50, what is the discounted pr
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20 divided 100 = .2 then u multiply 16.5 by .2 =3.3 then u subtract that from 16.5 and u get 13.2
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