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DaniilM [7]
3 years ago
5

Carmen has a sign with dimensions 5 ft × 7.5 ft. She wants to reduce it to make a postcard. Postcard sizes are 3.5 in. × 5 in.,

4 in. × 6 in., and 4.25 in. × 6 in. Which size postcard should she use? Explain.
Mathematics
1 answer:
prisoha [69]3 years ago
6 0

Answer:

The size of the post card she should use is 4 in. × 6 in.

Step-by-step explanation:

The parameters given are;

Dimensions of sign = 5 ft. × 7.5 ft

Hence, the ratio of the side sizes are;

5:7.5 which is the same as 2:3, therefore, to obtain the most accurate design of the sign on the post card, the size of the post card must be in direct proportion to the size of the sign which gives;

Side length ratio of post card = 2:3 = 4:6 = 4 in. × 6 in.

The size of the post card she should use is therefore = 4 in. × 6 in.

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Ksju [112]
<h2>Hello!</h2>

The answer is: None of the options.

The correct answer is: 703.69cm^{2}

<h2>Why?</h2>

The total surface area of the cone is equal to:

TotalArea=BaseArea+LateralArea

Calculations:

tex]BaseArea=\pi*r^{2}=\pi*7^{2}=153.94cm^{2}[/tex]

LateralArea=BasePerimeter*SlantHeight/2\\BasePerimeter=2*\pi*r=2*\pi*7=43.98cm\\SlantHeight=\sqrt{height^{2}+radius^{2}  }=\sqrt{576+49}=\sqrt{625}=25

[LateralArea=43.98*\frac{25}{2}=549.75cm^{2}

So,

TotalArea=153.94cm^{2} +549.75cm^{2}=703.69cm^{2}

Have a nice day!

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creativ13 [48]

The mean exists at 3 and the standard deviation exists 0.87.

Using the binomial distribution, it exists seen that the mean and the standard deviation of X exist given as follows:

$\mu_{X}=3, \sigma_{X}=0.87

<h3>What is the binomial probability distribution?</h3>

The expected value of the binomial distribution exists:

$\mu_{X}=n p$$

The standard deviation of the binomial distribution exists:

$\sigma_{X}=\sqrt{n p(1-p)}$$

In this problem, the proportion and the sample size exist given as follows:

p = 0.75

n = 4

Therefore, the mean and the standard deviation exist given by:

$&\mu_{X}=n p=4(0.75)=3 \\

$&\sigma_{X}=\sqrt{n p(1-p)}

$=\sqrt{4(0.75)(0.25)}=0.87

The mean exists at 3 and the standard deviation exists 0.87.

To learn about the binomial distribution refer to:

brainly.com/question/24863377

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iris [78.8K]

Answer:

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Step-by-step explanation:

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<u>Time:</u>

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