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alina1380 [7]
2 years ago
8

3) Solve the equation for x. 10(4x + 4) = 400 A) 2 B) 4 C) 9 D) 18

Mathematics
2 answers:
pishuonlain [190]2 years ago
5 0

Answer:

C) 9

Step-by-step explanation:

10(4x + 4) = 400

40x + 40 = 400

40x = 360

x = 9

adoni [48]2 years ago
5 0

Answer:

First factor out the expression

(10•4x)+(10•4)=400

40x+40=400

Then solve

40x+40=400

-40 = -40

40x=360

------ ------

40 40

x=9

C) 9

☆anvipatel77☆

•Expert•

Brainly Community Contributor

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What is an equation of the line that passes through the points (-1, -2) and (2, 4)
olasank [31]

Answer:

y = 2x

Step-by-step explanation:

Formula is y = mx + b

m is slope

slope = (4 - -2) / (2 - -1) = 6 / 3 = 2

Now equation is y = 2x + b

To find b, substitute one of the coordinates in the equation. Let's use (2,4)

y = 2x + b

4 = 2(2) + b

b = 0

So equation is y = 2x

3 0
3 years ago
In Triangle XYZ, measure of angle X = 49° , XY = 18°, and
marissa [1.9K]

Answer:

There are two choices for angle Y: Y \approx 54.987^{\circ} for XZ \approx 15.193, Y \approx 27.008^{\circ} for XZ \approx 8.424.

Step-by-step explanation:

There are mistakes in the statement, correct form is now described:

<em>In triangle XYZ, measure of angle X = 49°, XY = 18 and YZ = 14. Find the measure of angle Y:</em>

The line segment XY is opposite to angle Z and the line segment YZ is opposite to angle X. We can determine the length of the line segment XZ by the Law of Cosine:

YZ^{2} = XZ^{2} + XY^{2} -2\cdot XY\cdot XZ \cdot \cos X (1)

If we know that X = 49^{\circ}, XY = 18 and YZ = 14, then we have the following second order polynomial:

14^{2} = XZ^{2} + 18^{2} - 2\cdot (18)\cdot XZ\cdot \cos 49^{\circ}

XZ^{2}-23.618\cdot XZ +128 = 0 (2)

By the Quadratic Formula we have the following result:

XZ \approx 15.193\,\lor\,XZ \approx 8.424

There are two possible triangles, we can determine the value of angle Y for each by the Law of Cosine again:

XZ^{2} = XY^{2} + YZ^{2} - 2\cdot XY \cdot YZ \cdot \cos Y

\cos Y = \frac{XY^{2}+YZ^{2}-XZ^{2}}{2\cdot XY\cdot YZ}

Y = \cos ^{-1}\left(\frac{XY^{2}+YZ^{2}-XZ^{2}}{2\cdot XY\cdot YZ} \right)

1) XZ \approx 15.193

Y = \cos^{-1}\left[\frac{18^{2}+14^{2}-15.193^{2}}{2\cdot (18)\cdot (14)} \right]

Y \approx 54.987^{\circ}

2) XZ \approx 8.424

Y = \cos^{-1}\left[\frac{18^{2}+14^{2}-8.424^{2}}{2\cdot (18)\cdot (14)} \right]

Y \approx 27.008^{\circ}

There are two choices for angle Y: Y \approx 54.987^{\circ} for XZ \approx 15.193, Y \approx 27.008^{\circ} for XZ \approx 8.424.

6 0
3 years ago
Which equation represents a circle with a center at (–4, 9) and a diameter of 10 units?
ale4655 [162]

Answer:

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Step-by-step explanation:

The standard form for a circle is

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In your case, h = -4 and k = 9 and r = 5

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7 0
3 years ago
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How to get the equation
Olenka [21]
ITS EASY AND IF YOU TRY YOU CAN FIND THE ANSWER JUST WORK HARD AND TRY
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Answer:

Step-by-step explanation:

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3 years ago
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