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Oksana_A [137]
3 years ago
5

Can you draw a trapazoid with 3 sides

Mathematics
2 answers:
Dima020 [189]3 years ago
8 0

No. If it has three sides, then it's a triangle, and not a trapezoid.


kap26 [50]3 years ago
6 0
No you can't draw a trapezoid with 3 sides because that would be a triangle.

hope this helped
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Help! :(<br><br> It’s in the pic :3
Harlamova29_29 [7]

Answer:

\frac{3}{2}

Step-by-step explanation:

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3 years ago
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Thank you for any help!
mash [69]

The answer is D

0 is not less than or equal to -4, and in the second equation, 0 is greater than -1

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3 years ago
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Round 123,949 to the underlined point. 4 is highlighted
ehidna [41]

\\ \sf\longmapsto 123,949

  • 9 is greater than 5

\\ \sf\longmapsto 123,95

  • 5=5

\\ \sf\longmapsto 123,9

  • 9 is greater than 5

\\ \sf\longmapsto 124

  • 4 is less than 5

\\ \sf\longmapsto 12

  • 2 is less than 5

\\ \sf\longmapsto 1

Note

Write the number until underlined point.I did it till end

5 0
3 years ago
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A lighthouse casts a 128-ft shadow. A nearby lamppost that measures 5
olga nikolaevna [1]

Answer: 80 feet

Step-by-step explanation:

We can write these as fractions and do cross multiplication with the numerator being the height of the object while the denominator being the length of the shadow:

5 * 128 = 8x

640 = 8x

80 = x

Thus, the height of the lighthouse is 80 feet tall.

8 0
3 years ago
Suppose the standard deviation of a normal population is known to be 3, and H0 asserts that the mean is equal to 12. A random sa
blagie [28]

Answer:

z=\frac{12.95-12}{\frac{3}{\sqrt{36}}}=1.9  

p_v =P(z>1.9)=0.0287  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 12 at 5% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=12.95 represent the sample mean

\sigma=3 represent the population standard deviation for the sample  

n=36 sample size  

\mu_o =12 represent the value that we want to test  

\alpha=0.05 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is equal to 12, the system of hypothesis would be:  

Null hypothesis:\mu \leq 12  

Alternative hypothesis:\mu > 12  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{12.95-12}{\frac{3}{\sqrt{36}}}=1.9  

P-value  

Since is a right tailed test the p value would be:  

p_v =P(z>1.9)=0.0287  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 12 at 5% of signficance.  

4 0
3 years ago
Read 2 more answers
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