3)the line G & H are parallel
4) Parallel line theorem is what I do believe it's called (do you have choices for this one?)
To find the relation between them, you need transform them to the same currency. Let's transform them to cents.
$3.60 = 360 cents.
One quarter is 25 cents, and one nickel is 5 cents.
So 360 = 25q + 5n
Hope this helps! :D
Answer:
<h2>5 quarts</h2>
Step-by-step explanation:
Let's think through this bit by bit.
<em>10 lbs * 16 oz/lb = 160 oz. of apples.</em>
In the proportion below, we can see we simply divide by 8, in terms of magnitude.
8 oz -> 1 cup
160 oz -> 160/8 -> 20 cup
20 cups! Is it the answer? NO! They're asking for it in units of <em>quarts, not cups.</em>
We must remember that 1 quart = 4 cups.
20 cups * 1/4 qt/cups = 5 quarts
The technique of matrix isolation involves condensing the substance to be studied with a large excess of inert gas (usually argon or nitrogen) at low temperature to form a rigid solid (the matrix). The early development of matrix isolation spectroscopy was directed primarily to the study of unstable molecules and free radicals. The ability to stabilise reactive species by trapping them in a rigid cage, thus inhibiting intermolecular interaction, is an important feature of matrix isolation. The low temperatures (typically 4-20K) also prevent the occurrence of any process with an activation energy of more than a few kJ mol-1. Apart from the stabilisation of reactive species, matrix isolation affords a number of advantages over more conventional spectroscopic techniques. The isolation of monomelic solute molecules in an inert environment reduces intermolecular interactions, resulting in a sharpening of the solute absorption compared with other condensed phases. The effect is, of course, particularly dramatic for substances that engage in hydrogen bonding. Although the technique was developed to inhibit intermolecular interactions, it has also proved of great value in studying these interactions in molecular complexes formed in matrices at higher concentrations than those required for true isolation.
Answer:
a) A student travelling to school on public transport: 15/52 or 0.231
b) A student walking to school: 16/52 or 0.308
c) A student not cycling to school: 43/52 or 0.827
Step-by-step explanation:
Total people = 52
Travel Method Frequency
Public Transport 12
Car 15
Cycle 9
Walk 16
Find the relative frequency of.
The formula used will be: 
a) A student travelling to school on public transport:
Given Frequency: 12
Size of sample space: 52
Apply formula:
Fraction = 12/52
Decimal = 0.231
b) A student walking to school
Given Frequency: 16
Size of sample space. 52
Apply formula:
Fraction = 16/52
Decimal = 0.308
c) A student not cycling to school.
We will consider all students except those who cycle.
12+15+16 = 43
Given Frequency: 43
Size of sample space. 52
Apply formula:
Fraction = 43/52
Decimal = 0.827
