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3 years ago

5

P divided by 1 2/3 = 2 1/5

2 answers:

sergejj [24]3 years ago

6 0

Answer:P, 1 2/3 +2 1/5 Mixed number form

Step-by-step explanation:

Vlada [557]3 years ago

4 0

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There are 12 boys enrolled in algebra 2

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3 years ago

Use the PACED decision-making process to _____.

Alex_Xolod [135]

Use the PACED decision-making process to make a decision or make a choice. The steps to follow when making a decision can be easily remembered when you use the word PACED:
P - What is the PROBLEM - Why is there a need to make a choice?
A - What are the ALTERNATIVES - What are the possible choices available?
C - Establish the CRITERIA - Why is one choice better than the other?
E - EVALUATE the alternatives - How well does each choice meet the criteria?
D - Make a DECISION - What is the best choice?

6 0

3 years ago

The number of bacteria in a certain culture doubled every hour. If there were 30 bacteria present in the culture initially, how

vichka [17]

Answer:

The number of bacteria after $8th$ will be $3840$

Step-by-step explanation:

Given the initially 30 bacteria present in the culture.

Also, the number of bacteria got doubled every hour.

So, using the equation

$A=A_0r^{n-1}$

Where $A$ is number of bacteria after $n$ hours.

$A_0$ is bacteria present initially.

$r$ is the common ration, in our problem it is given that bacteria doubles every hour. So, $r=2$

And $n$ is the number of hours. In our problem we need amount of bacteria at the end of $8th$ hours. So, $n=8$

Plugging values in the formula we get,

$A=30(2)^{8-1}\\A=30\times 2^7\\A=30\times 128\\A=3840$

So, number of bacteria after $8th$ will be $3840$

3 0

3 years ago

Ifyou are asked to solve a system ofequations in which there is no linear equation to start with, you can sometimes begin by iso

maw [93]

What you typped is correct

7 0

3 years ago

For which rational expression is 8 an excluded value ? check all that apply

denis23 [38]

<u>Answer:</u>

The correct answer options are C. $\frac{x^2+5}{x-8}$ and D. $\frac{x^2-x-56}{x^2-64}$ .

<u>Step-by-step explanation:</u>

The values which make the denominator equal to zero are called the excluded values.

Here, we can substitute 8 for x and check if it makes the denominator 0.

$\frac{x-8}{x+8} = \frac{8-8}{8+8} =\frac{0}{16} =0$

$\frac{x-2}{x^2-4} = \frac{8-2}{8^2-4} =\frac{6}{60} =\frac{1}{10}$

$\frac{x^2+5}{x-8} = \frac{8^2+5}{8-8} =\frac{69}{0}$

$\frac{x^2-x-56}{x^2-64} = \frac{8^2-8-56}{8^2-64} = \frac{0}{0} =0$

$\frac{8x^2-2}{x^2-16} = \frac{8(8)^2-2}{8^2-16} =\frac{510}{48}$

7 0

3 years ago