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ivanzaharov [21]
3 years ago
5

Lim x>0- ((x+deltaX)^2+x+deltaX-(x^2+x))/deltaX

Mathematics
1 answer:
Andre45 [30]3 years ago
6 0
<span>((x+deltaX)^2+x+deltaX-(x^2+x))/deltaX = (x^2 + 2x delta x + (delta x)^2 + x + delta x - x^2 - x) / delta x = delta x (2x + delta x + 1) / delta x = 2x + delta x + 1

Therefore, </span>Lim as x tends to 0 of <span>((x + delta X)^2 + x + deltaX - (x^2 + x)) / deltaX</span> = 1 + delta x
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These are angles, segment, triangles, etc that have exactly the same measures matches to Congruent

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Two angles whose measures add up to 180° matches to straight angle  

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kicyunya [14]

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8 0
3 years ago
The perimeter of a parallelogram is 180 cm. One side exceeds the other by 10 cm. What are the lengths of adjacent sides of the p
Georgia [21]

Answer:

one side is 40 other is 50

Step-by-step explanation:

perimeter=180cm

let one side=length=x

Acc. to condition:

other side=width=x+10 (one side exceed other by 10)

perimeter= 2(length+width)

subtitue all values given above:

180=2(x+x+10)

180=2(2x+10)

2x+10=180/2

2x+10=90

2x=90-10

2x=80

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now

lenght=x=40cm

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width=50cm

8 0
3 years ago
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