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ivanzaharov [21]
3 years ago
5

Lim x>0- ((x+deltaX)^2+x+deltaX-(x^2+x))/deltaX

Mathematics
1 answer:
Andre45 [30]3 years ago
6 0
<span>((x+deltaX)^2+x+deltaX-(x^2+x))/deltaX = (x^2 + 2x delta x + (delta x)^2 + x + delta x - x^2 - x) / delta x = delta x (2x + delta x + 1) / delta x = 2x + delta x + 1

Therefore, </span>Lim as x tends to 0 of <span>((x + delta X)^2 + x + deltaX - (x^2 + x)) / deltaX</span> = 1 + delta x
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34kurt

Answer:

x = 25

Step-by-step explanation:

We know that A and M are on a line, which is 180 degrees, and the little square means 90 degrees. So, ∠RAM = 180 - 90 = 90 degrees.

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Now, simply combine like terms and solve for x:

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<em>~ an aesthetics lover</em>

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Answer:

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Step-by-step explanation:

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x=4

Step-by-step explanation:

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