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ivanzaharov [21]
2 years ago
5

Lim x>0- ((x+deltaX)^2+x+deltaX-(x^2+x))/deltaX

Mathematics
1 answer:
Andre45 [30]2 years ago
6 0
<span>((x+deltaX)^2+x+deltaX-(x^2+x))/deltaX = (x^2 + 2x delta x + (delta x)^2 + x + delta x - x^2 - x) / delta x = delta x (2x + delta x + 1) / delta x = 2x + delta x + 1

Therefore, </span>Lim as x tends to 0 of <span>((x + delta X)^2 + x + deltaX - (x^2 + x)) / deltaX</span> = 1 + delta x
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